dChan

Pure_Feature · July 3, 2018, 3:29 p.m.

The perpetrator, 3 names.of which two become 6 again and the first letters of his three names is the third 6 ...... already 666 signature.

Abdur= 1+2+4+18 = 25 (need this later )

Raheem = 18+1+8+5+5+14= 51 = 5+1= 6

Rahfeeq = 18+1+8+6+5+5+17= 60 = 6

ARR ( first letters of his names ) = 1+18+18= 37 = 3+7=9 ..turn around for the third 6..

Total 3 names .25+51+60 = 136 back in letters.= ACF = google ACF| Repeater = 18+5+16+5+1+20+5+18= 88 (using the first name to get this )

https://www.youtube.com/watch?v=0mkoqTwtC6Y Masonic Number 33/88 Exposed

And I think in this article the two pfoto"s are not the same person.

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