Anonymous ID: 375670 Dec. 23, 2017, 2:02 p.m. No.159145   🗄️.is 🔗kun

>>159127

I know

 

If the function is linear every -5 off the countdown is +-10 days.

 

If we are at 5 right now. -5 (to 0) is 10 days.

 

If we find the [15] marker we can check if the function is linear or maybe exponential. In that case the countdown can end tonight!

Anonymous ID: 375670 Dec. 23, 2017, 2:06 p.m. No.159181   🗄️.is 🔗kun   >>9190 >>9191

We need the date of the [15] marker.

 

[10] was on 12/12/2017

[5] is on 23/12/2017

 

+- 10 days difference

 

-5 to [0] marker is +-10 days if function is linear.

 

We need that [15] marker to verify the function of the countdown.

Anonymous ID: 375670 Dec. 23, 2017, 2:15 p.m. No.159241   🗄️.is 🔗kun   >>9249 >>9257 >>9283 >>9360

>>159223

What date is that?

 

4 november the princes got arrested

 

Let's assume 4 november is the [15] marker

 

so

 

[15] = 4/11/2017

[10] = 12/12/2017

[5] = 23/12/2017

 

DELTA

 

[15] to [10] = 28 days

[10] to [5] = 10 days

[5] to [0] = ?

 

28 / 3 = 10

10 / 3 = 3

 

So COUNTDOWN WILL END IN 3 DAYS!