>>16599935

Agent 47

For the film, see Hitman: Agent 47.

Agent 47

Hitman character

Agent 47 in Hitman Absolution.png

Agent 47 in promotional art for Hitman: Absolution (2012)

First appearance Hitman: Codename 47 (2000)

Created by IO Interactive

Designed by Jacob Andersen

Portrayed by Timothy Olyphant (Hitman)

Borislav Parvanov (Hitman, young)

Rupert Friend (Hitman: Agent 47)

Jesse Hergt (Hitman: Agent 47, young)

Voiced by David Bateson

In-universe information

Alias Tobias Rieper

Mr. Byrd

Flech Fischer

Mr. Julio

Jacob Leiter

Dr. Cropes

Mr. Johnson

Stan Johnson

Species Human (clone)

Occupation Contract killer, spy

Affiliation Providence (unwillingly; formerly)

International Contract Agency / ICA (formerly)

Relatives DNA donors / "Fathers":

Otto Wolfgang Ort-Meyer

Lee Hong

Pablo Belisario Ochoa

Frantz Fuchs

Arkadij Jegorov

Clones / "Brothers":

Lucas Grey / Agent 6

Agent 17

Agents 48

Born September 5, 1964 (age 57)

Satu Mare, Romanian People's Republic

Agent 47 (or simply 47) is a fictional character and the player protagonist of the Hitman video game franchise, developed by IO Interactive. He has been featured in all games of the series, as well as various spin-off media, including two theatrically released films. Agent 47 has been voiced by actor David Bateson in the video game series.

A monotone and seemingly emotionless contract killer, the player controls 47 as he travels around the world to execute hits on various criminals, both big and small, that are assigned to him by Diana Burnwood, his handler within the fictional International Contract Agency (ICA). The character takes his name from being the 47th clone created as part of an experiment funded by various wealthy criminals that sought to create an army of obedient soldiers to carry out their commands. As one of the last clones to be created, 47 is also among the most skillful, and manages to escape his creators before finding employment with the ICA. Throughout much of the series, 47's backstory is shrouded in mystery, with occasional new elements about his dark past being revealed in each entry. This is due to 47 himself having very little recollection of his life before the events of the games.

Agent 47 has been positively received by critics and fans alike for his moral ambiguity and nuanced characterization. Alongside other gaming character with similar traits, such as Lara Croft, Sam Fisher, and Solid Snake, he is considered one of the most popular and significant characters in the entire video game industry.

(cont…)

https://en.wikipedia.org/wiki/Agent_47

>>16600359

47 - Dr. Bentley’s Proof

Author: Dr. Troglodyte ()

Date: August 23, 2013 12:47AM

In 1964, Dr. Donald Bentley, Professor of Statistics, Pomona College, presented the following paradoxical proof: ”Why all numbers are equal to 47” (as recalled by David Hart, Pomona ’92)

Quote

”Draw an isosceles triangle, with points ABC, with line AC representing the "base" of the triangle. By definition, side AB and side BC are equal length, and angle BAC and angle BCA are equal to each other.”

Quote

”Assign the smaller of whatever two numbers you intend to prove to the base, line AC. Let's choose…oh, I don't know, maybe 47. Assign the larger number (let's say 74) to the pathway A-B-C. In other words, divide the larger number by 2 and assign that (37 in our example) to line AB; by definition, line BC is then also 37. So, the distance along line AC is 47. The distance along the path from A to B to C equals 74.

Next, bisect each of the three sides. Assign points D,E,F to the midpoints of lines AB, BC, and AC respectively. Draw lines DF and EF. Now, by definition, line AF and line FC are equal (both equal to 23.5, half of 47). Also by definition, line AD and line EC are equal (both half of 37, therefore 18.5). We already established that angles BAC and BCA are equal to each other, therefore by the geometry rule "side-angle-side", triangles ADF and FEC are congruent triangles. Therefore, line EF and line DF are also congruent, and both are equal to 18.5.

Now, step back and answer the question: What is the total length of the path along the line ADFEC? Well, it's four congruent lines, each equal to 18.5, for a total of 74. This is the same length as the original path along A to B to C.

Now, bisect lines AD, DF, FE, EC, AF, and FC. Label the midpoints as follows: midpoint of AD = G. AF = H. DF = I. FE = J. FC = K. EC = L. Now draw the lines GH, GI, JK, and KL. By the same geometric rules and problem solving, triangles AGH, HIF, FJK, and KLC are all congruent, and every line AG, GH, HI, IF, FJ, JK, KL, and LC is equal to 1/2 of 18.5 = 9.25. Now the total path along the line AGHIFJKLC is still 74.

If you continue this process, making infinitely smaller isosceles triangles, and still calculating the path along the line of these triangles from A to C, you still get 74. Now, here's the crux of the argument: In the limit, you arrive at two paths along the route from point A to point C. The original line AC is still 47. But, the path from point A to point C along the other route is always equal to 74. Therefore, 47 and 74 are equal to each other. By the same logic, any number can be shown to be equal to 47 (or any other number).”

Dr. Troglodyte

https://grahamhancock.com/phorum/read.php?6,902589,902589