more vortex math incoming.
is magic square that mason sudoku showing interconectedness of groups?
numbers are a thing. so basic though.
<3
There is Pythagoras with right angle 90 degree triangle, working with those three digits summed up being 12, having 3^2 + 4^2 = 5^2 work. then there is Fermets theorem on this working with being qubed, x^3 + y^3 = z^3.
how to go from ^2 to ^3 when it´s a plane?
where to go? weighting sort of?
could there be like interchanging tiltedness of a plane that is inbewteen all those lines forming that triangle?
like there being a line with 3 lenght, and a line with 4 lenght, but not connected to it but with a "helpline" in between that is bc of 3 being angled in any way and not "landing" on that 4 lenght line but sort of above or below.
this helpline due to a plane that is not defined tilted for those points but sort of being tiltedness as an Eigenschaft itself?
this would then be sort of having 3 and adding +1 as a line within those triangle lines (not inbetween two lines exactly, but inbewteeen them by being inbewtweenness) or maybe not even +1 but rather +2, as 3 could be seen as a clock sort of circle with three bended arrows pushing each other in a selfadjusting running way. +1 would make two 2-lines (0 1, forth back, info) out of those in sum 4 arrows, now three having formed the circle + 1 are two and two. when wanting to keep the circlyness of that number 3 you would not have to add one more arrow making that circle become two 2-lines, you would have to add +2 to have that circle stay a circle and have that +1 not mess the 3ness up, I guess.
when having 3+1, that +1 sort of goes superpositioned into this 3-thing.
when going from 9 to 10 it´s three selfadjusted circles of each 3 moving arrows pushing each others and one +1 that could turn every of the three circles into a 0 1 info thing having two arrows. (those arrows than are shown in a circle or bended like way, bc it seems the intended movement can hardly be perceived it truly having those two arrows above each other on a line.)