Anonymous ID: 79b11d July 15, 2025, 11:01 a.m. No.23330046   🗄️.is 🔗kun   >>0072

t=0

draw=_=>{background(0,t++?.03:!createCanvas(W=720,W)+W)

colorMode(HSB)

noStroke()

filter(BLUR)

for(d=H=360;d-=30;)for(r=0;r<TAU;r+=2/d)fill(d,50,W,1/(T=tan(d/199-t/99)2))+circle(cos(R=r-PI/2)(D=d+sin(r9+t/9d/W)d/4noise(r99,d)T)+H,sin(R)D+H,2)}

Anonymous ID: 79b11d July 15, 2025, 11:18 a.m. No.23330130   🗄️.is 🔗kun

>>23330072

0 rem this program displays the pixels of the current characterset

10 dim bytes(7) : px$ = "{reverse on}{black}{207}" : sp$="{reverse on}{light blue}{207}"

20 print"{clear}{white}enter screen code: ";

22 rem

25 rem the following poke turns off the ? after input:

30 poke 19,32 : input c : print chr$(13)

32 rem

35 rem source address for character data

40 addr=53248+c*8

45 rem

48 rem turn off keyboard and IO temporarily

50 poke 56334,peek(56334)and254

60 poke1,peek(1)and251

65 rem

68 rem grab the character data for the chosen char (c)

70 for row = 0 to 7 : bytes(row) = peek ( addr+row) : next row

75 rem

78 rem turn keyboard and IO back on

80 poke1, peek(1) or 4

90 poke 56334, peek(56334) or 1

92 rem

94 rem now lets print out the data

95 print : print tab(15);

98 rem

99 rem 8 rows of 8 pixel bits …

100 for row = 0 to 7 : for p = 7 to 0 step-1

105 rem

108 rem if row and 2 to the power of pixel is a 1

110 if (bytes(row) and 2^p) then print px$; : goto 130

120 print sp$;

130 next p : print : print tab(15); : next row

140 print chr$(13)tab(7)"{reverse on}{light blue} press a key to continue {reverse off}{light blue}"

150 poke 198,0

160 wait 198,1

170 get a$

180 goto20