Anonymous ID: 8502ee Dec. 2, 2025, 5:21 p.m. No.23933426   ๐Ÿ—„๏ธ.is ๐Ÿ”—kun   >>3569

>>23933384

Thanks Fren.

Anons and even Clowns would benefit by just picking a minute mark and reading all the drops on that minute mark, the drops on the minute mark across from it, AND [15] from each of those.

It is NOT a prediction tool. Never has been.

:13, :28, :43, and :58 is a great example.

Anonymous ID: 8502ee Dec. 2, 2025, 6:05 p.m. No.23933667   ๐Ÿ—„๏ธ.is ๐Ÿ”—kun

>>23933569

Not that I have found. Please post an example on the QClock.

To go deeper. One has to count all the [markers] on the [15] and see if it is an odd or even amount. A=1, B=2, C=3 and so on. This includes [MM] for example. 1313/15=87.5333333

15x87=1305

1313-1305=8

[MM] could be 8 ahead or 8 back depending if there is an odd amount of [MM[s or an even amount.

Drop 2524

[2] completed= 2 is even and if you have completed something you can move ahead.

[1] coming= 1 is odd and if you are still coming you are behind.

 

Gets a bit brain taxing.