Reposting from an old bread as an avenue for further dissection; could use additional fleshing out per the OP.
Q Research General #2980 Home of the Gold Star Researchers Edition!!!
https://8ch.net/qresearch/res/2364722.html#2364830
QPROOF
What I am about to prove is not 100% completed (I made rough assumptions on average vs rare vs exotic, and on trump's twitter breakdown), however, is still factually based
What are the odds that Q uses the same two words as Trump in a 240 character twitter post, within an hour of Trump posting
240 possible characters
2000 words are average words
2000-10000 are rare words
10000-40000 are exotic words (such as names)
average words average about 4 characters and 1 space
rare words average about 6 characters and 1 space
exotic words average about 7 characters and 1 space
For any given post, of 240 characters, lets assume:
80% average words
15% rare words
5% exotic words
Let us further assume, on average, only 60% of the characters are used in a tweet, which gives us:
2400.80.6 / 5 = 23.04 average words
2400.150.6 / 7 = 3.08 rare words
2400.050.6 / 8 = 0.9 exotic words
Lets assume that probability of matching an average word is 0.01137416192 (23 possible words as N, 2000 possible word choices as probability of success)
Lets assume that probability of matching an rare word is 0.0003749062559 (3 possible words as N, 8000 possible word choices as probability of success)
Lets assume that probability of matching an exotic word is 0.0000333333 (1 possible words as N, 30000 possible word choices as probability of success)
Lets take the rogue example
The probability of the rogue example, assuming that rogue is a rare word, is about 0.037% chance to occur
At the moment, there are over 15 examples like this, given 15 examples, the probability just using average words is 0.0000000000000000000000000000000000000000000000003%
To give this a further proof, only 3 examples of coincidence would provide about 0.00000565%
If you workers are familiar with 6 sigma process, 6 sigma is used to ensure no defects ever occur.
6sigma is 99.99966%, which assumes success
That means, the chance of failure (to be considered success) is 0.00033%
The probability of Q being a Larp based on just a few examples is stastically impossible.
The probability of being a conspiracy theory is 0.
The probability of being a conspiracy theory is 0.