QPROOF
edited from >>2364830 (Bread #2980) with Today's information
What I am about to share is not 100% completed work (I made rough assumptions on word classifications, and did not conduct an actual machine learning based word or sentence embeddings on trump's & Q's posts), however, should be factually based with enough information to quell even the toppest of kek anons.
What are the odds that Q uses the same two words as POTUS in a 240 character twitter post, within an hour of POTUS posting?
If you factory workers or engineers are familiar with 6 sigma process, 6 sigma is used to ensure no defects ever occur.
6sigma is 99.99966%, which assumes success
That means, the chance of failure (to be considered success) is 0.00033%
Time Based Chance
Now, lets consider 3 posts that happen from Q within 1 minute before POTUS in a row.
For simplicity lets assume the following:
There are 24 hours in the day, yet assume it is known that POTUS only posts in 10 hour window
Assume POTUS averages about 10 tweets per day, or 1 post per hour.
Your chance of posting 1 minute before trump is 1 in 60 or 1.67% chance
Your chance of posting 1 minute before trump, two times in a row is 1 in 3600 or 0.028% chance
Your chance of posting 1 minute before trump, three times in a row is 1 in 216000 or 0.0004630% chance -just about equal to 6sigma
IF THAT DIDNT CONVINCE YOU… KEEP READING FELLOW NERD
Word Choice Chance
240 possible characters
Assuming that within the English dictionary that…
2000 words are common words
2000-10000 are rare words
10000-40000 are exotic words (such as names)
common words average about 4 characters and 1 space
rare words average about 6 characters and 1 space
exotic words average about 7 characters and 1 space
For any given post, of 240 characters, lets assume:
80% common words
15% rare words
5% exotic words
Let us further assume, on average, only 60% of the characters are used in a tweet, which gives us:
2400.80.6 / 5 = 23.04 common words
2400.150.6 / 7 = 3.08 rare words
2400.050.6 / 8 = 0.9 exotic words
Lets assume that probability of matching a common word is 0.01137416192 (23 possible words as N, 2000 possible word choices as probability of success)
Lets assume that probability of matching an rare word is 0.0003749062559 (3 possible words as N, 8000 possible word choices as probability of success)
Lets assume that probability of matching an exotic word is 0.0000333333 (1 possible words as N, 30000 possible word choices as probability of success)
Lets take the rogue example
The probability of the 'rogue' example, assuming that 'rogue' is a rare word, is about 0.037% chance to occur
At the moment, there are over 30 examples like this, given 30+ examples, the probability just using average words is 0.0000000000000000000000000000000000000000000000003%
To give this a further proof, only 3 examples of coincidence would provide about 0.00000565%
The probability of Q being just a COINCIDENCE is statistically impossible.