Anonymous ID: 682f6b March 5, 2019, 11:57 a.m. No.5522380   🗄️.is 🔗kun

>>5522102

Not a math fag, but I think there's a problem with this approach. I remember something about the odds of rolling doubles with dice. If you are asking what are the odds of rolling two ones, 1 in 36, then this math works, but if you are asking for the chance of rolling any double with a six sided die, then it does not work. The odds of the first die rolling a number is always 1, so the odds of a double are just the chance of the second die matching the first which is a one in 6 chance, not a one in 36.

I'm pretty sure that the same logic applies to the chance of a Q post matching a Potus tweet.

With 4642 Potus tweets we'd need to calculate the probability that ANY 18 of the 2969 Q posts would hit at the same time.

Anonymous ID: 682f6b March 5, 2019, 12:14 p.m. No.5522593   🗄️.is 🔗kun

>>5522102

Wouldn't you calculate it like this?

Fraction of total minute during which Potus posts: 711360/4642= 1 out of every 153 minutes.

Number of times that Q would post during one of those minutes 2969/153=19.

Since we have 18 zero deltas, the occurence of those zero deltas would appear to be almost exactly what one would expect from random chance.

Anonymous ID: 682f6b March 5, 2019, 12:27 p.m. No.5522747   🗄️.is 🔗kun

>>5522102

The more I think about it, it would seem like your probability calculation is for the chances of both Q and Potus posting on a specific minute. For instance, I think your math would be correct to calculate the chances of both Q and Potus posting at exactly 1:23PM today with a zero delta.

However, your calculation does not take into account the fact that we are not looking at a single specified minute but the chances of the zero delta taking place during ANY of the 711360 possible minutes.

Now, that said, if Q and Potus both post at 1:23PM today . . . that would be mathematically vanishingly improbable.