Anonymous ID: 3c4e35 June 21, 2019, 4:14 p.m. No.6810596   🗄️.is 🔗kun

e is the derivative of the grid

so it makes sense that the amount of steps is governed by a natural logarithm

Anonymous ID: 3c4e35 June 21, 2019, 4:32 p.m. No.6810736   🗄️.is 🔗kun

d, e is the input

the trivial element is the value we don't want

the non-trivial element is the value we want

how do we use all the surrounding elements, cells, rows and columns (the qubits) to perform the Fourier transform? Where does the grid perform the QFT? Somewhere foundational? (1,1)?

Anonymous ID: 3c4e35 June 21, 2019, 4:33 p.m. No.6810753   🗄️.is 🔗kun

Imagine that the amount of elements you need to use to calculate the factors of an RSA-4096 bit number can be calculated by hand.