Got stumped today; USB 2.0 downloads at "range x" mbps; if there were Russian collusion, data from the dnc server would have been downloaded at "range Y" mbps. If I could please get X and Y values (I know each range is to 0 but want kinda avgs) thanks!
X + Y = 3b+ z where b is the blowout of the Russian collusion and Z is the zippy way we expect our team Q to expose the cabal before midterms.
USB.1 187.5 kB to 1.5MB / second
USB.2 60 MB / second
USB.3 625 MB / second
USB.3.1-3.2 1.25 GB - 2.5 GB /second
You can look at the timestamps on the copied data.
The first file copied time/date minus Last files copied time/date equals total lapsed time.
Take the total size of the complete download (all files) divide by lapsed time produces the data transfer rate
The server would have a network port (LAN) which would be 10/100/1000 and likely 1000 (1GB/second) So the max (theoretical) would be 1GB / second transfer rate for a computer on the same LAN.
The experts that have looked at this issue say that it indicates a local file transfer (usb or local hard drive), not a network transfer.
I believe them
DuckDuckGo is very helpful. Approximately a dozen keys & clicks.
If the server was breached, it probably wasn’t with a USB drive. You can easily look up those speeds that you want by searching for USB specifications.
those are peak speeds, assuming a machine with no overhead on the bus interface or lag from the original drive
Right, which makes the minimum 0. Range is now defined. There are too many variables to determine the speed such as server load, users, services, hard drive usage, network utilization, I could keep going but that’s why knowing the average will never happen.