Anonymous ID: 211561 Jan. 2, 2018, 9:19 p.m. No.2346   🗄️.is 🔗kun   >>2347 >>2349 >>2363

>>2342

That formula is basically this one

>>1929

But for the F side you would do X ≈ floor(sqrt(abs(F)*(N)))

 

Every A/B value in (E/F, 1) is a valid N, along with the factors of A/B. Along with any A/B values of any N cell in that E/F. The problem is divining which N to factor with, or which X in (E/F, 1) is the correct one to factor against.