So we can generate any cell in (e,1). Since we know that N = (XX+E)/2A, wouldn't that mean that 2NA = XX+E ?
Could we navigate to the cell where our new X is the same as our original D. Then we would have that that is divisible by N and A
So we can generate any cell in (e,1). Since we know that N = (XX+E)/2A, wouldn't that mean that 2NA = XX+E ?
Could we navigate to the cell where our new X is the same as our original D. Then we would have that that is divisible by N and A
Problem with this is that (at least for c=145) the X values are odd and this would require them to be even (cuz our d is 12). In this case I believe we could go to our F record (basically d=d+1) to get the record where X is the same as the original D.