ProgramMathAnon !dSvrkhSLR6 ID: 769a5e Jan. 16, 2018, 10:40 a.m. No.3049   🗄️.is 🔗kun

>>3045

Continuing with the d[t]-d) analysis.

 

Pic related is reconfigured test case for c=145 showing values where:

 

DN = (d[t] - d) mod (n-1) == 0

AN = a mod n == 0

 

Not seeing anything yet.

ProgramMathAnon !dSvrkhSLR6 ID: 769a5e Jan. 16, 2018, 5:05 p.m. No.3055   🗄️.is 🔗kun   >>3056 >>3058

See pics related for continued analysis of (e,1).

 

Examples are for c=65 and c=145.

 

Reminder for calculations we are comparing:

 

Calculation 1: (d[t]-d)/(n-1)

Calculation 2: a[t]/n

 

where d and n are the values from our entry record at (e,n). And d[t] and a[t] are from the (e,1) record being analyzed.

 

Only records where (n-1) and n are factors are shown.

 

Notes:

 

a) There are 2 sequences for each calculation.

b) One sequence increments by 1 and then is multiplied by a factor.

c) The other sequence increments by 2 and then is multiplied by a different factor.

d) Lines marked as "overlap" are where both calculations have (n-1) and n as factors.

 

Example:

 

c=145

 

the d[t] sequences are incremented by factors of 18 and 24.

the a[t] sequences are incremented by factors of 100 and 44.

 

No clue what to do with this information.

ProgramMathAnon !dSvrkhSLR6 ID: 769a5e Jan. 16, 2018, 5:27 p.m. No.3057   🗄️.is 🔗kun   >>3058

>>3056

I really don't know.

 

First step is trying to understand what VQC was even talking about.

 

If this analysis is correct, then somewhere in here is an "offset" that gives us a connection to the prime solution.

ProgramMathAnon !dSvrkhSLR6 ID: 769a5e Jan. 16, 2018, 5:33 p.m. No.3058   🗄️.is 🔗kun   >>3059 >>3060

>>3055

>>3056

>>3057

It's possible that the sequences for a/n add up to c-1.

 

c=65:

Sequence 1 factor = 36

Sequence 2 factor = 28

Total = 64 + 1 == c

 

c=145:

Sequence 1 factor = 100

Sequence 2 factor = 44

Total = 144 + 1 == c

ProgramMathAnon !dSvrkhSLR6 ID: 769a5e Jan. 16, 2018, 5:44 p.m. No.3060   🗄️.is 🔗kun

>>3058

Also possible that for a/n, factor for sequence 1 comes from record (e,1,t+n) and factor for sequence 2 comes from record (e,1, n-t+1).

ProgramMathAnon !dSvrkhSLR6 ID: 769a5e Jan. 17, 2018, 3:25 p.m. No.3077   🗄️.is 🔗kun

Possible formula for the underlying factors to determine where a[t] % n == 0.

 

Pic related.

 

factor 1: 4*x

factor 2: (x-1)^2

 

Not sure if relevant.

ProgramMathAnon !dSvrkhSLR6 ID: 769a5e Jan. 18, 2018, 11:49 a.m. No.3093   🗄️.is 🔗kun   >>3094 >>3240

Making a little progress.

 

Pics show various examples of the different factors for (d[t]-d) and a[t] formulas.

 

The formula (x^2 - f) can be used to find a valid factor of (d[t] - d). Sometimes it is the first valid factor below a record at (e,1, t+n).

 

How is this useful?

 

I believe we are searching for a formula for d.

 

For example, 901=17x53

 

Starting positions:

 

from c=901

(1,421,15) = {1:421:30:29:1:901}, f = 60

 

records at t = c.n + c.t

(1,17,436) = {1:17:23184:871:22313:24089}

(1,421,436) = {1:421:1772:871:901:3485}

 

Example formula that solves for the d value of (1,17,436) = 23184.

 

x^2-f = 29*29 - 60 = 781

 

(d)*(x^2 - f) - ( 2 * ( c - ( x^2 - f ) ) + 1 ) - 5

 

30(781) - (2(901 - 781) + 1) - 5

 

30*781 - (240+1) - 5

23430 - 241 - 5 = 23184

 

The 241 value is the next valid factor of d[t] - d after 781.

The 5 is just a value I added to the end because the numbers are really close. I was thinking of 2^2 + 1, or could be that one of the other formulas is wrong.

ProgramMathAnon !dSvrkhSLR6 ID: 769a5e Jan. 19, 2018, 10:52 a.m. No.3114   🗄️.is 🔗kun

>>3113

I understand the recursion, but it's not going to be the solution.

 

If you get a chance, take a look at some of my screenshots. There are a number of paths to matching records that I've identified, but none that are consistent for different test cases.

 

If I'm reading the QVC hint correctly, the solution can be calculated from the na record.

ProgramMathAnon !dSvrkhSLR6 ID: 769a5e Jan. 19, 2018, 11:53 a.m. No.3117   🗄️.is 🔗kun   >>3118

Found an interesting relationship between the c na record and the prime solution na record.

 

Pic is for c=145 example, but it applies everywhere.

 

Maybe this is obvious.

 

{1:1:72:11:61:85}

{1:1:32:7:25:41}

 

d = 72 - 32 = 40

x = 11 - 7 = 4

a = 61 - 25 = 36

b = 85 - 41 = 44

 

d-x = a

d+x = b

 

And if you look at the value of (x^2 - f) compared to the diff in d, the numbers are very close to a d[t] - d value in the list of valid factors of (d[t]-d) / (n-1).

ProgramMathAnon !dSvrkhSLR6 ID: 769a5e Jan. 19, 2018, 2:23 p.m. No.3119   🗄️.is 🔗kun   >>3133 >>3149

>>3118

>I’m in till we finish this. Then on to more math fun!

VA - I agree completely! This problem has truly been an eye opener for me. Couldn't care less about RSA.

ProgramMathAnon !dSvrkhSLR6 ID: 769a5e Jan. 19, 2018, 4:37 p.m. No.3130   🗄️.is 🔗kun

>>3129

Thanks VA.

 

Seems like the d[t] hint is exposing some real power behind the scenes in the grid. Wish we knew more.

ProgramMathAnon !dSvrkhSLR6 ID: 769a5e Jan. 19, 2018, 4:54 p.m. No.3132   🗄️.is 🔗kun

>>3131

VA - Excellent summary and understanding.

 

>is there supposed to be a (n-1)*a connection for d[t]?"

This is exactly what we are searching for. I still believe there is an elegant formula.

 

But notwithstanding the d[t] hint, I haven't found any combination of steps that is repeatable across different test cases.

ProgramMathAnon !dSvrkhSLR6 ID: 769a5e Jan. 19, 2018, 5:49 p.m. No.3134   🗄️.is 🔗kun   >>3137 >>3192

Latest test case of c=145 attached.

 

Still looking at the differences between c at na, and prime at na.

 

Added tests to compare the differences in d, a, and b against differences in x.

 

(d-d)/(x-x)

(a-a)/(x-x)

(b-b)/(x-x)

 

Another humorous references to the boiling point of vinegar? Coincidence?

ProgramMathAnon !dSvrkhSLR6 ID: 769a5e Jan. 22, 2018, 9:02 a.m. No.3206   🗄️.is 🔗kun

>>3204

-x records seem to "line up better" than records in x. At least they give different target numbers to try and match to. See one of my sample pics.

 

You can create any corresponding -x record simply via an (e,n,t) formula.

 

for even e:

 

newT = 2 - t

 

for odd e:

 

newT = 1 - t

ProgramMathAnon !dSvrkhSLR6 ID: 769a5e Jan. 22, 2018, 4:10 p.m. No.3229   🗄️.is 🔗kun   >>3230 >>3233

Attached are latest analysis of d[t]-d and a[t] for c=145, c=533 and c=6107. Just to give examples for various values of e.

 

These records are generated via a regular (e,1,t) function where t values begin from the original c at t=c.t + c.n, and then into negative t.

 

Included are differences for x and x/2, as well as those differences in a binary view where zeros are spaces, and 1's are #.

 

It looks like:

 

one of the sequences for a[t] is based on multiples of x.

one of the sequences for d[t]-d is based on multiples of (x+1).

 

There can be more than 2 interwoven sequences as the numbers get larger. See c=6107 as an example.

 

Not sure if this is adding any clarity.

ProgramMathAnon !dSvrkhSLR6 ID: 769a5e Jan. 22, 2018, 5:19 p.m. No.3231   🗄️.is 🔗kun

>>3230

>Are we stalled on finding a connection between c and p records? That jump between the two seemed like t-2 for the examples given.

VA - Unfortunately, the more I dig into the data, the further away a solution seems. So much to learn.

ProgramMathAnon !dSvrkhSLR6 ID: 769a5e Jan. 23, 2018, 9:29 a.m. No.3234   🗄️.is 🔗kun   >>3235 >>3239

>>3233

Thank you.

 

I've continued to look at the d[t] and a[t] differences and explored binary and factors of each.

 

Attached are latest tests for c=145, 533 and 6107.

 

I've added columns for t diff, t diff in binary, and t diff factors.

 

The factors are interesting, as they sometimes match the original x, x+1, x-1, d, d+1, or d-1 values indicated as [x], [x+], [x-], [d], [d+], [d-] respectively. I've also highlighted perfect square factors. Example is 4^(2) which indicates a 2x2 square.

 

Really interesting is the c=6107 example where a factor of 197 exists as a t diff factor in the d[t] - d analysis, and a factor of 31 exists as a t diff factor in the a[t] analysis.

ProgramMathAnon !dSvrkhSLR6 ID: 769a5e Jan. 23, 2018, 2:12 p.m. No.3237   🗄️.is 🔗kun   >>3239

>>3236

I compared records at (e,1), (e,a), (e,b), (e,n), and (e,c) specifically because they share e, x and 2na values.

 

Figured that if we reduced the movement in variables, the solution would present itself. But I haven't been able to come up with a formula for d changes that accurately describes more than a few test cases.

 

I'm also leaning towards the offset being a difference in t or x. And will spend a bit more time on the (p * i + t, p * i + 1 - t) formulas you mentioned above.

 

Perhaps there is also something to be learned from looking at the difference between (-e,0) and the prime solution.

ProgramMathAnon !dSvrkhSLR6 ID: 769a5e Jan. 24, 2018, 3:44 p.m. No.3270   🗄️.is 🔗kun   >>3271 >>3274

>>3268

Just ran a quick test to confirm your records.

 

Here is some sample output for a=5, b=23. Also notice the -5 change in na.

 

(15,4,3) = {15:4:10:5:5:23} = 115; f=6; (x+n)=9; na=20; f+c=121; -x=-13

(-6,3,4) = {-6:3:11:6:5:23} = 115; f=29; (x+n)=9; na=15; f+c=144; -x=-12

(-29,2,4) = {-29:2:12:7:5:23} = 115; f=54; (x+n)=9; na=10; f+c=169; -x=-11

(-54,1,5) = {-54:1:13:8:5:23} = 115; f=81; (x+n)=9; na=5; f+c=196; -x=-10

(-81,0,5) = {-81:0:14:9:5:23} = 115; f=110; (x+n)=9; na=0; f+c=225; -x=-9

 

>>3269

>There's only meant to be one value of negative e too, for a given static a and b.

This doesn't appear to correct. There is only 1 valid at n=0.

ProgramMathAnon !dSvrkhSLR6 ID: 769a5e Jan. 24, 2018, 3:59 p.m. No.3277   🗄️.is 🔗kun

>>3274

Thanks. That -x calculation is used to jump into the -x space. It's calculated as -(x + 2 * n); I'll remove as it's confusing.

ProgramMathAnon !dSvrkhSLR6 ID: 769a5e Jan. 24, 2018, 4:52 p.m. No.3283   🗄️.is 🔗kun   >>3284 >>3289

>>3282

Very interesting. Thank you for sharing this.

I've been able to reproduce the movement down to n=0.

 

Have you taken a look in the opposite direction?

 

newE = e + (2*d - 1)

newD = d - 1

newX = x -1

 

These entries literally go on for ever.

ProgramMathAnon !dSvrkhSLR6 ID: 769a5e Jan. 24, 2018, 5:26 p.m. No.3290   🗄️.is 🔗kun   >>3296 >>3344

>>3289

If I am following you correctly, your new e formula enables a jump directly to the corresponding n=0 record using values of e, n and d.

 

But how is this a solution when the a and b values are still unknown?

 

What am I missing?

ProgramMathAnon !dSvrkhSLR6 ID: 769a5e Jan. 25, 2018, 11:02 a.m. No.3348   🗄️.is 🔗kun   >>3352

>>3300

Looked a bit further into (f,1) records, and analyzing the d[t] and a[t] differences.

 

See pics related for c=145, showing diffs at (e,1), (f,1) and (0,1).

 

In (f,1), there are more occurrences of the 5 factor in d[t] - d. But unfortunately, that pattern doesn't extend to other test cases. For c=6107, no records appear.

 

Similarly in (0,1) we get some matches at d[t]-d, but none at a[t].