Anonymous ID: 9f7aa6 Jan. 17, 2018, 7:16 a.m. No.3070   🗄️.is 🔗kun   >>3072

I found what he's talking about.

For (E,N,D,X,1,C) (our start record) in (E,1) there is always a record (e,1,d,x,a,b) where

D-d = N-1

and

a = N

Anonymous ID: 9f7aa6 Jan. 17, 2018, 7:42 a.m. No.3072   🗄️.is 🔗kun   >>3073 >>3087

>>3070

 

(1, 61, 12, 11, 1, 145, 144)

 

X = 7

(1, 1, 32, 7, 25, 41, 16)

(1, 5, 12, 7, 5, 29, 24)

NA = 25

Goal:

(1, 1, 32, 7, 25, 41, 16)

 

1 1 72 11 61 85 24

-60 60 61 61

 

I meant D-d = -(N-1)

Anonymous ID: 9f7aa6 Jan. 17, 2018, 8:17 a.m. No.3073   🗄️.is 🔗kun

>>3072

Also in this cell the X's are the same as the (a,b)=(1,c) cell. Then we can go straight to that cell through

 

(E,N,D,X,A,B)

to

 

(knowing (d-D = N-1 =N+D-1 = d)

(also since d-x=a we have: N+D-1-X = a

(E, 1, N+D-1, X, N+D-1-X, ?)

 

You could then just calculate B however you want.