Anonymous ID: 4958e4 Feb. 19, 2018, 8:28 a.m. No.4798   🗄️.is 🔗kun   >>4799 >>4801

>>4790

(x+n)(x+n) = nn + 2dn - 2d + 2d + 1 - e

xx + 2xn + nn = nn + 2dn - 2d + 2d + 1 - e

xx + 2xn = 2dn + 1 - e

xx + e = 2dn - 2xn + 1

xx + e = 2(d-x)n + 1

xx + e = 2an + 1

 

Isn't it true that

xx+e = 2an, so maybe this is false and you added an extra 1