I also keep coming back to this:
starting record at c=145
(1,61,6) = {1:61:12:11:1:145}
na transform to (1,1,6)
(1,1,6) = {1:1:72:11:61:85}
prime solution at a=5,b=29
(1,5,4) = {1:5:12:7:5:29}
na transform to (1,1,4)
(1,1,4) = {1:1:32:7:25:41}
Thinking out loud here…
For c record (1,c)
[t] is the same in (e,1) and (e,n)
x[t] is the same in (e,1) and (e.n)
d[t] in (e,1) is original d (12) + (61-1) = transformed d = 72
a[t] = na = 1*61 = 61
For prime record:
[t] is the same in (e,1) and (e,n)
x[t] is the same in (e,1) and (e,n)
d[t] in (e,1) is original d (12) + (n-1)*a
transformed d is 12+ (5-1)*5 = 32
a[t] = na = 5*5 for transformed a
is there supposed to be a (n-1)*a connection for d[t]?
This part is the key i think:
na transform to (1,1,6)
(1,1,6) = {1:1:72:11:61:85}
Then to this:
na transform to (1,1,4)
(1,1,4) = {1:1:32:7:25:41}
Thoughts? If the factor tree can help us bridge the gap between x=11 in (e,1) and x=7 in (e,1) we've got it. For this example, delta x = 11-7 = 4.
Thoughts?