>>4693

I'd note here, the (F,E) parity matches the (D,E) parity.

A little contribution I have for B,

We know B = C/A, we also have B = A+(2(X+N)), but I've also come across B = D+X+(2N), which I don't think I've seen anywhere before.

>>4712

Nope, that bitch is super old. Here's some fucking organization because lord knows we lack it.

A = C / B

A = D – A

A = ((X^2 + E) / (N * 2);

B = C / A

B = ((X + N) * 2) + A

B = (N * 2) + D + X

C = A * B

C = D^2 + E

C = (D + N)^2 – (X + N)^2

D = floor(sqrt(C))

D = A + X

E = C – D^2

F = C – (D + 1)^2

F = E – (2 * D) + 1

N = ((A + B) / 2) – D

N = (X^2 + C) / (2 * A)

X = D – A

X = floor(sqrt((D + N)^2 – C)) – N

X ≈ sqrt(E*(N-1))

X ≈ floor(sqrt(abs(F)*(N)))

next X = sqrt((2 * N * B) – E)

previous X = X - (sqrt((2 * N * B) - E) - X)

>>4722

>A = D – X

ftfy.

>>4744

That's because (2d-1) + d^2 + e + 2d(n-1) + n^2-1 is an alternate form of (d + n)^2 + e - 2. So this would apply to any 2 cells shared in an E column.

Does anyone have any interest in a VQCGUI_v3? One that is a bit more… accurate? Just don't want to put the time into it if no one will use it.

>>4764

X+N=

1059731506988603553937431268657920267324681542931

(X+N)^2=

1123030866904336703079469523070416463095627144114722409357226718814587956951689069474054796070761

(N-1)*8=

115100708248095715653845476953416823881690247480

((X+N)-1/2)*8=

4238926027954414215749725074631681069298726171720

((N-1)8) + (((X+N)-1/2)8) + 1 =

4354026736202509931403570551585097893180416419201

>>4765

This is using the RSA100 solution numbers.

>>4768

Verified true in all cells. Is also able to be reduced 2 d n = 2 n x + x^2 + e

>>4775

I dun goofed. Time for bed~

(x+n)^2 = n^2 + 2d(n-1) + f - 1 is true for all cells. At least, I'm pretty suuuuuure.

>>4777

The technically correct version is (x+n)^2 = n^2 + 2d(n-1) + abs(f) - 1