Anonymous ID: 6c52f4 April 29, 2018, 2:33 p.m. No.5700   🗄️.is 🔗kun   >>5704 >>5710 >>5711

>>5695

CA Here, like usual doing my own thing. Have we tried this algorithm?

 

Take your start value c. Then make values e,n,d,x,a,b. Make a new value (c-n). Repeat with (c-n). It works a decent amount. But the problem is dealing with the parity because to make a record you need (a,b) to have the same parity. I've so far just taken away the largest power of 2 that I can from the number and I make the next record b-n.

CA !LAbIRp9cT. ID: 6c52f4 April 29, 2018, 5:23 p.m. No.5704   🗄️.is 🔗kun   >>5705 >>5706 >>5707 >>5710

>>5700

 

Start with e,n,d,x,a=1,b=c

Then I make a new value from H = b-n.

Then from here I need to factor H (recursion) and get m (a factor of H)

Then, we make a new record e,n,d,x,a,b = AB(1,H/m)

Then make new value H=b-n

Factor H to get m

rec = AB(1,H/m)

etc..

 

At each step, if you check the gcd of the original number with each of H, n, and b one of these will have the result. I tried with the first 3741 coprimes and it worked