CollegeAnon !LAbIRp9cT. ID: 6fc1ab May 8, 2018, 11:22 p.m. No.5848   🗄️.is 🔗kun   >>5849

>>5819

Holy shit that first key seems HUGE.

 

This equation works for A,B and D values.

A/B/D(t) = T(t)4 + tconst + start

where T(t) =(t*(t+1))/2

 

I figured out a way earlier to calculate the constant and start for each (e,1) record I just don't have it on hand. These are known values.

 

an = A(t) = T(t)4 + tconst + start

= 2t(t+1) + t*const + start

bn = A(t+n) = T(t+n)4 + (t+n)const + start

= 2(t+n)(t+n+1) + (t+n)*const + start

b = a + 2n + 2x

so

bn = an + 2nn + 2xn

 

2(t+n)(t+n+1) + (t+n)const + start = 2t(t+1) + tconst + start + 2nn + 2xn

(2t+2n)(t+n+1) + tconst + nconst + start = 2t(t+1) + t*const + start + 2nn + 2xn

[2tt] + 2tn + [2t] + 2tn + [2nn] + 2n + [tconst] + nconst + [start] = [2tt] + [2t] + [t*const] + [start] + [2nn] + 2xn

4tn + 2n + n*const = 2xn

4t + 2 + const = 2x

4t + 2 + const = 2d - 2a

 

Idk if this helps but I think the algebra is correct.

 

I forgot what the calculation for t was.

CollegeAnon !LAbIRp9cT. ID: 6fc1ab May 8, 2018, 11:27 p.m. No.5849   🗄️.is 🔗kun

>>5848

If x is odd (d even), then t = (x-1)/2,

so 4(x-1)/2 + 2 + const = 2x

 

2x - 2 + 2 + const = 2x

const = 0

FUCK