VA !!Nf9AmQNR7I ID: a5b148 March 7, 2018, 8:40 p.m. No.5141   ๐Ÿ—„๏ธ.is ๐Ÿ”—kun   >>5142

Hello lads! Working and thinking over here. I have a few good new ideas, just working on testing them first. Thinking on the (x+n) square and this:

>Then fill the square with n0^2 and multiples of 2d.

I'm thinking of n0^2 as little squares inside the bigger (x+n) square. Like doing a block puzzle with n0^2 pieces and 2d sized pieces. Or maybe 2d(n0-1) pieces?

VA !!Nf9AmQNR7I ID: a5b148 April 4, 2018, 3:59 p.m. No.5431   ๐Ÿ—„๏ธ.is ๐Ÿ”—kun

>>5428

Hello PMA! I'll start working on smaller examples of this:

>Breaking the problem down.

>First by roots.

>Then by triangular numbers.

 

I think that the "levels" of each root and remainder could be helpful in eliminating unnecessary calcs. Maybe our desired (x+n) is 1) a multiple of the lowest levels of the factor tree (or GCD) and 2) a triangular number. Process of elimination. Maybe the factor tree aids in more efficient searching, not providing an answer up front.

VA !!Nf9AmQNR7I ID: a5b148 April 7, 2018, 8:08 a.m. No.5469   ๐Ÿ—„๏ธ.is ๐Ÿ”—kun

>>5467

>If there was some way we could turn every operation into a small n value search, then I think we would have our solution

This is where the (e,1) connection has to come in. Row 1 is the โ€œone row to rule them all.โ€