VA !!Nf9AmQNR7I ID: 5eaea8 July 2, 2018, 9:30 p.m. No.6635   🗄️.is 🔗kun   >>6637 >>6652

>>6634

Yup, I agree.

Hmm. Here's where my mind is at.

I'm thinking the next step is to find SQRT d and any remainders. Somehow they help unlock the next step.

 

For the END:

We solved the E by moving from e to negative f and finding the matching records

N is finding the an, bn, a(n-1), and b(n-1) pattern

D is using sqrt d to unlock how to move from the na transform to the correct records for either a(n-1), b(n-1), etc.

If we can move to the correct record, we got this solved.

 

Here's the idea I'm working on, just putting this out there, needs more verification:

c287

d=16, sqrt d=4

I think maybe we move from our (-2,1) -f na transform, which is t=8 a=127,

to t[8+4] = t[12] = 287

Whaddya know, it's our b(n-1) value.

Which means in (31,1) we go to t[8+4+1]=328

328-287= 41 = b

287/41 = 7= a

solved.

(for this example, lol! Needs more testing)