New thinking on c145:
(1,c) to (na) to negative e.
We find our prime a and b at {-111:1:16:11:5:29} = 145
So maybe we just run the search into negative e until we find our matching c record?
Easy to do, because you can see the c values declining (by a set amount) each 2n you move left.
"maybe we'll c something we didn't before" ??
It's like a countdown, actually.
We just move left, looking for our (prime) c, and tracking progress by watching c decline as we move.
We could eventually just write a formula to calc where the correct -e record would be.
Then we use a and b to plug in with the correct d=12, and solve the problem.
d=12 - a=5 = x=7
(5+29)/2-12 = n = 5
{1:5:12:7:5:29}
i "c" an element (-111,1,6) with matching c , a, and b records to our prime element.