VA !!Nf9AmQNR7I ID: 97dd9b June 24, 2018, 4:58 p.m. No.6482   🗄️.is 🔗kun   >>6483 >>6487

>>6470

>"Note that a[t] at (-f,1) is related to d[t] at (e,1) and is keyed by the value of d for a particular c. The value of f is determined by d. Since d contains a+x, this is the key."

 

Check out this element, I was very close to the right idea:

{-119:1:12:11:1:25}

correct prime d value here, d = 12

Then we go back to (e,1) and look for 25 in the a column.

At (1,1,4) we have {1:1:32:7:25:41} which has x=7 and t=4

 

so na = 25

at e=1, na is n=1 and a=25

only other combos are n=5 a=5

or n = 25 a=1

prime n =5, prime a =5

and correct x should be 7, which it is.

 

I know it's a bit of a stretch, but I'm just trying to find the connection.

Thoughts?

 

Also, here's the other possible factorization for na, n=25 a=1 found it right where it should be at (1,25,4) {1:25:8:7:1:65}

VA !!Nf9AmQNR7I ID: 97dd9b June 24, 2018, 5:13 p.m. No.6483   🗄️.is 🔗kun   >>6488

>>6482

Here's a better set of images. To recap, I started at the c145 na transform in (e,1) [highlighted turquoise].

Then I moved left into negative e, hopping 2n to the left until I found d=12 (our prime d value).

Here's the element: {-119:1:12:11:1:25}

a=1 b=25 [this one is not shown, too far]

Then I moved back to (e,1) to look for 25 as a factor.

I found it at {1:1:32:7:25:41} (highlighted orange). Interesting to note that this element has the same x as our correct (prime) element.

 

then i used our idea of na to break 25 into it's factors. 1x25 5x5 25x1. So there are only 3 possibilities for na locations. n=1, n=5, n=25.

 

Sure enough, at n=5 we find our (prime) element {1:5:12:7:5:29}

We also find the other na possibility, n=25 where it is expected to be: {1:25:8:7:1:65}