Isee !kIkD/SqZ4s ID: bead22 May 16, 2018, 10:17 a.m. No.6029   🗄️.is 🔗kun   >>6030

>>6015

I keep thinking about this stuff.

 

To re-iterate a bit, take a cell like a=7, b=37.

 

It has the following cell:

(3, 6, 16, 9, 7, 37)

 

We'll call this cell_0. Now let's use the knowledge that (x+n) for cell_0 is the equation:

n(2d + n) - e (ref >>5995).

 

So we make a new cell, cell_1 with a = n, b = 2*d + n. For our example of a=7, b=37. This will be:

(3, 7, 15, 9, 6, 38)

 

Let's show them side, by side:

cell_0 = (3, 6, 16, 9, 7, 37)

cell_1 = (3, 7, 15, 9, 6, 38)

 

So they actually share a lot of properties.

 

The d in cell_0 is equal to (x + n) from cell_1. d + n is the same for both (meaning they share the big square (d+n)^2).

 

The n in cell_1 is equal to the a in cell_0 and the a in cell_1 is equal to the n in cell_0.

 

The difference between n in cell_0 and cell_1 is the same as the difference between d's and thus a's and b's for cell_0 and cell_1.

 

I'm wondering if we might know enough to start deducing the properties between them. Like a fancy ass math sudoku. I'm thinking towards some kind of elimination system, but it's been years since I actually used any of those.

 

As always, I might be off my rocks ;)