VQC said it was, so I put it in the list. I'll track down the post.
>Given two columns f+e or 2d+1 apart (-f and e)
>How can we tell or construct the list of factors in a[t] that are 1 unit apart?
Two columns means two e values regardless of n. So that means two e values 2d+1 apart. One e can have infinite d values, so I have to assume we're meant to pick a cell in order to have a corresponding d, f and a[t]. If I pick an arbitrary cell like {5:1:4:1:3:7}, its d is 4, so we need a column 9 cells to the left (into negative space), giving us the column at f = -4. The t value of that positive cell is 2, and (-f, 1) starts at t=3 in this case. So either I'm not understanding you or it's irrelevant. Not to mention, if there was a t=2 cell at (-f, 1), following how d increases at an increasing rate in those cells and applying the pattern into negative space, d would equal 2, and 2d+1 in this case is 5, so it's a different offset from the positive cell. Something's weird about this.
VQC, I feel like half the time you post, I try to implement what you're saying and it doesn't make any sense based on the way I seem to be interpreting your explanations, nobody else points it out or they read into it differently and start finding results from it regardless, and it never gets addressed again. It's very frustrating.
I forgot to say, thank you for checking my work. I'm glad someone is. I have a feeling this giant set of equations all being utilized on any c is pretty vital to getting this done. Then VQC comes back and drops even more things to check, of course. I guess we can just keep adding to it.