VA !!Nf9AmQNR7I ID: d88a7c May 18, 2018, 10:48 p.m. No.6045   🗄️.is 🔗kun

>>6043

Ok. let's break this excellent PMA image down.

(7,8,15) {7:8:82:29:53:127}

nn = 64

nn div 8 = 8

nn mod 8 = 0

(2d-1)(n-1) = (164-1)(7) = 1141

1141 div 8 = 142

1141 mod 8 = 5

(n-1) = 7

(n-1) div 8 = 0

(n-1) mod 8 = 7

(f-1) = 2d-e = 82*2-7 = 157

157 div 8 = 19

157 mod 8 = 5

mods total: 0 + 5 + 7 + 5 = 17

(17-1) / 8 = 2

so each 1Tu gets 2 units of mods, middle square gets 1 unit

Each 1Tu gets 8 units of nn

Each 1Tu gets 142 units of (2d-1)(n-1)

Each 1Tu gets 0 units of (n-1)

Each 1Tu gets 19 units of (f-1)

So for each 1Tu, the sum is:

8 + 142 + 0 + 19 = 169 for the div 8's, PLUS 2 units from the mods ( 17-1 div 8 ) = 171

171 * 8 + 1 (for the middle unit) = 1369

SQRT(1369) = 37

x+n = 37

Yeah, that works!

VA !!Nf9AmQNR7I ID: d88a7c May 26, 2018, 8:39 p.m. No.6172   🗄️.is 🔗kun   >>6174

>>6169

Alright GA. Post the output to show your point, lol! Show us the relation between D[t]-d and the triangular numbers.

 

Are the T(s) based on (f-1)? Cause if so you got a winner.

VA !!Nf9AmQNR7I ID: d88a7c May 26, 2018, 8:44 p.m. No.6175   🗄️.is 🔗kun

>>6174

Keep Going, GA! I've struck out plenty of times. Better to swing for the fences tho. This team is perfect for the job. Let's swing for the fences tonight, faggots. ;)

VA !!Nf9AmQNR7I ID: d88a7c May 28, 2018, 7:40 p.m. No.6207   🗄️.is 🔗kun   >>6209

Sure Anon! You gonna dox yourself? Agenices are here, but whatever since we know about Vault 7 & 8. Let's hear the song.

VA !!Nf9AmQNR7I ID: d88a7c June 1, 2018, 7:26 p.m. No.6242   🗄️.is 🔗kun   >>6243 >>6244

VQC's last post >>6185 clearly said we need two algebra equations to solve this. Good job Isee working this out.

 

Also, fabulous work GA on this new app, and thanks for posting your code too.

>>6238

>https://pastebin.com/czpK8A4j

 

You're using Python, correct?

VA !!Nf9AmQNR7I ID: d88a7c June 9, 2018, 11:34 a.m. No.6297   🗄️.is 🔗kun

>>6292

Hello Anons! As VQC asked, here's the grid from (-5,1) to (5,1) with c values included to help us "c" something new?

VA !!Nf9AmQNR7I ID: d88a7c June 14, 2018, 7:07 p.m. No.6352   🗄️.is 🔗kun

>>6351>>6351

Hello AA! Sorry for not replying sooner, my IRL has been super nuts with work. I think your explanatory Guide is a great idea. Maybe we can collaborate on the dough for the next bread?? I think we can mention the discord, and keep in mind that all significant ideas should be posted here on the board. This is our home.

 

I have also given a lot of thought to what will happen when we solve this. VQC said "New Math Kangz". Here's my thought on the issue: This is tech that has been suppressed, and Q team has decided that now is the time to release this knowledge to the masses, for the advancement and evolution of humanity. VQC will not take compensation, but gave us free will to choose how we will use this solution. VQC fished us all in with excellent bait, back on CBTS. WHY??? Because they needed a crazy ass team that could handle WAY FUCKING OUT THERE ideas without batting an eye. That's us. The fact that we're still here working, collaborating, and focused on finding the keys to this solution is proof that he found the right Team. WE can do this, together!

 

You all know I've been feeling burnt and frustrated at the lack of finding a solution, and even went off on Saga because I was so pissed about it. But I was wrong to do that. You all know I've been the Cheerleader for this Quest since November, and you all know I'm All In 100%. Every good Myth or Story of the Hero's Quest involves much discouragement, but the hero always Perseveres, and Fate turns in his or her favor. We will Persevere until we Succeed.