Hey Lads, I just solved a really important old crumb!! Can I get some eyes on this please?
I solved for the d[t]-d = (n-1) = factors of a[t] in row (e,1).
My worksheet is attached.
There is a pattern in row 1 that directly gives us (n-1), and (n-1) is the main value used to create the next value of a, a[t+1]
Can Anons please help verify??
Here's the original crumb…
>Afternoon.
>As discussed previously.
>One way to find a solution is to use the grid or virtual quantum computer in the following way:
>Find the cell value at (e,1) where e is the remainder for c.
>You are looking for a[t] = na
>Remember
>At that value, d[t] = na+x
>Also
>At that value, x[t] = x, the x value in the cell is equal to the x value at (e,n)
>REMEMBER, the value of x at na in (e,1) is the SAME as x at (e,n)
>REMEMBER, take d from all values of d[t] at (e,1) and there is a known patter of (n-1) as factor in these values of d[t]-d that is different (increasingly) from the pattern of factors of n in a[t]. It is THIS that gives the offset that is used to solve the problem and thus get the cell at (e,1) to do all the work for you.