At any (e,n,t), there will be another record at (e,n,t+n) where that record's b is equal to the original record's a, and the new x is equal to the old one plus 2n (meaning 'b=b+2(x+2n)+2n, or b'b+2x+6n (b' being the new b and the others being the numbers from the original cell)). This creates an infinite sequence where each subsequent cell is (e,n,t+n) (adding n to t each time), and where each subsequent x is the last +2n. If you want to jump from one cell to another cell some arbitrary number of jumps away within (e,n), e and n will be the same, x will be the starting x plus the number of jumps from the original multiplied by 2n, and you can calculate a from xx+e=2na and b from b=a+2x+2n, so you can calculate the whole record.

Also of note is that the f at each new cell is equal to (the new x multiplied by 4) plus the old f.