>>7507

From (0,18720,1561) to (0,117,391), the difference between every value and any other value of that same variable is divisible by a.

This is the series of numbers the gap between the n values divided by a is equal to (from highest n to lowest n):

387, 448, 164, 25, 288, 11, 52, 56

Here's the same thing for t:

3, 7, 5, 1, 24, 2, 13, 35

Same thing for x:

6, 14, 10, 2, 48, 4, 26, 70

Same thing for a (but (next-current)/a since a gets larger as n decreases):

6, 14, 10, 2, 48, 4, 26, 70

Same thing for b:

780, 910, 338, 52, 624, 26, 130, 182

>>7507

We can find this d if we can find any c value. In (0,n), it'll be 11424400, and since e is zero, this is the minimum c value for our d. The maximum will be 11431160, since this is (3381*3381)-1 and after this point d=3381. So if we can find any c value within these two c values, we'll have a d value that is equal to the (an)(a(n-1)) we want.