Has anyone found anything to do with this clue?

>where the product of BigN and c are found in (e,1)

I'm using a=7, b=29, c=203 in this example. I'll do another example soon.

(7,4,4) = {7:4:14:7:7:29} f = -22

(7,88,7) = {7:88:14:13:1:203} f = -22

Product of BigN and c = 88*203 = 17864

Here’s (e,1) for this cell:

(7,1,1) = {7:1:5:1:4:8} f = -4

(7,1,2) = {7:1:11:3:8:16} f = -16

(7,1,3) = {7:1:21:5:16:28} f = -36

(7,1,4) = {7:1:35:7:28:44} f = -64

(7,1,5) = {7:1:53:9:44:64} f = -100

(7,1,6) = {7:1:75:11:64:88} f = -144

(7,1,7) = {7:1:101:13:88:116} f = -196

(7,1,8) = {7:1:131:15:116:148} f = -256

(7,1,9) = {7:1:165:17:148:184} f = -324

(7,1,10) = {7:1:203:19:184:224} f = -400

(7,1,11) = {7:1:245:21:224:268} f = -484

(7,1,12) = {7:1:291:23:268:316} f = -576

88 appears as b in (7,1,6) and as a in (7,1,7). 203 appears as d in (7,1,10). I don't know if 17864 itself appears though.

>>6905

a=13, b=43, c=559

(30,5,6) = {30:5:23:10:13:43} f = -17

(30,257,12) = {30:257:23:22:1:559} f = -17

Product of BigN and c = 257*559 = 143663

Here’s (e,1) for this cell:

(30,1,1) = {30:1:15:0:15:17} f = -1

(30,1,2) = {30:1:19:2:17:23} f = -9

(30,1,3) = {30:1:27:4:23:33} f = -25

(30,1,4) = {30:1:39:6:33:47} f = -49

(30,1,5) = {30:1:55:8:47:65} f = -81

(30,1,6) = {30:1:75:10:65:87} f = -121

(30,1,7) = {30:1:99:12:87:113} f = -169

(30,1,8) = {30:1:127:14:113:143} f = -225

(30,1,9) = {30:1:159:16:143:177} f = -289

(30,1,10) = {30:1:195:18:177:215} f = -361

(30,1,11) = {30:1:235:20:215:257} f = -441

(30,1,12) = {30:1:279:22:257:303} f = -529

…

(30,1,17) = {30:1:559:32:527:593} f = -1089

257 appears as b in (30,1,11) and as a in (30,1,12). 559 appears as d in (30,1,17). This does appear to be a pattern. I’m going to quickly put together a spreadsheet to extend these into further ts and see if I can actually find the product of BigN and c as the product, rather than the two separate variables.

Success with the product of BigN and c in (e,1)

>>6905

Here are some relevant cells for a=7, b=29, c=203

(7,1,94) = {7:1:17675:187:17488:17864} f = −35344

(7,1,95) = {7:1:18053:189:17864:18244} f = −36100

So for this one, the product of BigN (88) and c (203), which is 17864, does appear in (e,1). It appears as b at (7,1,94) and as a in (7,1,95). We can also say based on the algebra of x=d-a and the rules in (e,1) that a[t]=b[t-1] that BigN*c = d[94]+x[95] = d[95]-x[95]. So the increase in d from the first of these cells to the next is equal to 2x. These rules also apply to the example below.

>>6906

Here are some relevant cells for a=13, b=43, c=559

(30,1,268) = {30:1:143127:534:142593:143663} f = −286225

(30,1,269) = {30:1:144199:536:143663:144737} f = −288369

So for this one, the product of BigN (257) and c (559), which is 143663, does appear in (e,1). It appears as b at (30,1,268) and as a in (30,1,269). As I said, same rules with d[t]+x[t+1] and d[t+1]-x[t+1] apply.