Guys get this, for column 2, nd = 2t^2 + 2n*t + 1

this can somehow be generalized for even cells.

I feel like this is a BIG improvement, hopefully.

See where it says (2,3)? these are respectively t and n for d = 7. there are more integer solutions, I think one more if I'm not mistaken, the trivial solution.

For even e:

nd = 2t^2 + 2nt + (e/2)

For odd e:

nd = 2t^2 + 2(n-1)t - (n - ((e+1)/2))

anyone know how I can find integer solution of a given graph?

I don't want to put anyone's hopes down but the two formulas stated here >>7268 are merely the same as

x^2 + e = 2n (d-x)

which can be derived from this equation:

(d+n)^2 - (x+n)^2 = d^2 - e

Pic for c20737