Anonymous ID: 0aea66 Dec. 20, 2017, 11:33 p.m. No.818   🗄️.is 🔗kun   >>821 >>824 >>825 >>850

>>797

The multiple of 12 observation seems to be a robust conclusion for a of 5 or above. Between the 1cc and aabb cases, the difference in x works out algebraically to a^2-1, or (a+1)(a-1).

 

Since a is odd, because it's prime, both a+1 and a-1 are even, for two factors of 2. And one of a-1, a, or a+1 has to be a multiple of 3, and it can't be a because again, it's prime.

 

So a^2-1 has to be a multiple of 223 = 12. Neat.

Anonymous ID: 0aea66 Dec. 20, 2017, 11:48 p.m. No.825   🗄️.is 🔗kun   >>828

>>818

Actually the same logic can show that one of a+1 or a-1 has to be a multiple of 4, too. So the differences in x ought to all be divisible by 24.