VeritasAequitas !!Nf9AmQNR7I ID: 1d0be2 Dec. 19, 2017, 10:28 p.m. No.656   🗄️.is 🔗kun   >>658 >>660 >>681

Hey anons, just got some confirmation from VQC via Twatter. Check it out. I gotta go to bed now, but on it tomorrow am. This just came in.

VeritasAequitas !!Nf9AmQNR7I ID: 1d0be2 Dec. 20, 2017, 6:08 p.m. No.744   🗄️.is 🔗kun   >>747

>>729

>>742

>>743

 

I have no problem with establishing multiple new forums on the board for different discussions. I just don't think banning people from the main thread is the right approach. Thoughts, Anons?

VeritasAequitas !!Nf9AmQNR7I ID: 1d0be2 Dec. 20, 2017, 6:16 p.m. No.746   🗄️.is 🔗kun   >>748

>>725

Hello PMA! I have an idea, and was hoping for your expert assistance. Here it is, let me know if you think it's worth exploring.

 

For (1,1) and (1,2)

Can we get a breakdown of all factors of a and b for t=1-100? Factors listed for each t value for a and b in ascending order?

 

So like this:

(1,1,1) a factors = 1 b factors= 1*5

(1,1,2) a factors = 15 b factors= 113

(1,1,3) a factors= 113 b factors =15*5

 

up to t=100

 

Same thing for (2,1)

 

Do you think this is worth pursuing? If not, no worries!

VeritasAequitas !!Nf9AmQNR7I ID: 1d0be2 Dec. 20, 2017, 6:37 p.m. No.749   🗄️.is 🔗kun   >>750

>>748

Thanks PMA, agreed. The factors are easily calculated for smaller numbers. I was thinking along the lines of being able to explore the factors of a idea VQC keeps posting. Check this post:

 

>>495

>p will be a factor of a in elements:

>t+p, t+2p, t+3p,..

>and

>p+1-t, 2p+1-t, 3p+1-t,..

>Since xx+e = 2na, every cell in row (e,1) contains a catalog of all values of na for a remainder e within the value a for those elements.

 

"Every cell in (e,1) contains a catalog of all values of na for a remainder e within the value a for those elements" I'm working to understand this one crumb. Do you have any insight, PMA?

VeritasAequitas !!Nf9AmQNR7I ID: 1d0be2 Dec. 20, 2017, 7:01 p.m. No.751   🗄️.is 🔗kun   >>753

>>750

Thanks PMA. Also interesting, VQC keeps posting this idea about factors of a being related to t, but at the moment we only know that consistent t values exist in row 1 (e,1). "One row to rule them all."

 

Question: Does your method 1 apply to even e, and method 2 apply to odd e? We keep seeing that same pattern for t equations.

 

Working to understand, not fully understanding yet either. I think rather than using depth*p + orig.t, maybe we build a chain of factors and then use it to understand the pattern and create a formula. Thoughts?

 

Also, I'll join you looking for patterns in (0,n).

VeritasAequitas !!Nf9AmQNR7I ID: 1d0be2 Dec. 20, 2017, 7:52 p.m. No.759   🗄️.is 🔗kun

>>756

Yeah, Topolanon should be able to post in the main thread, and also bake his own thread for MysticalMath too. Thoughts?

VeritasAequitas !!Nf9AmQNR7I ID: 1d0be2 Dec. 20, 2017, 7:58 p.m. No.760   🗄️.is 🔗kun   >>761

>>758

Ok, so we have (e,1) the one row to rule them all. Factors of a are key.

Then we have column 0 or (0,n)

Explore values of c^2.

Let's get some work done, lads.

VeritasAequitas !!Nf9AmQNR7I ID: 1d0be2 Dec. 20, 2017, 9:17 p.m. No.763   🗄️.is 🔗kun   >>764

>>761

>>762

Great work PMA! Triangles are back in style?

 

Ok, so reading your output:

You proposed three connected tests, correct? PLS help if I'm getting any part wrong.

 

Test 1. In column 0, find any places where a=1 and c=c^2

Test 2.For all (e,n) find any places where a*b = prime solution

Test 3. In column 0, find any places where a = a^2 and b=b^2. So, looking for places later in t where the new a and b are squares of previous a and b.

 

a^2+b^2=c^2. Triangles definitely back in style.

 

So looking down your output further, I see matching c^2 groups: 4225, 21025, 616225, 811801, etc.

 

Your claim is that the first line is c^2, and then the second line is a^2+b^2.

 

X diff = 1,1,1,12.

 

Following, see a very clear pattern. Any thoughts on the next step?

VeritasAequitas !!Nf9AmQNR7I ID: 1d0be2 Dec. 20, 2017, 9:42 p.m. No.765   🗄️.is 🔗kun   >>766

>>718

>>761

Credit where credit is due, lads. Want to take a moment to say: Thank You!! to PMA and Teach, along with MA, CA, AA, Baker and all other Anons who have been working with the code and generating all the excellent output and graphics, along with formulas. You guys are way ahead of me in that arena. I'm following and understand the concepts clearly. I can help with good questions and pattern identification, along with formula creation.

 

TBH, I'm kinda wowed by all the talent here, and sometimes feel a little nervous to chip in or even ask questions. However, I have faith that I can continue to contribute value to our quest. So please bear with me when I may ask seemingly repetitive questions. I'm studying and re-reading VQC's crumbs all the time. Honestly, I just love math, and always have. That's why I'm here. Don't need/want glory etc. just want to help do my little part to help in the Q / VQC quest. Love you all. Glad to be here.

VeritasAequitas !!Nf9AmQNR7I ID: 1d0be2 Dec. 20, 2017, 10:12 p.m. No.774   🗄️.is 🔗kun   >>775 >>777

>>764

Nice PMA. So at the larger numbers, is t irrelevant? Was t like training wheels for learning how to ride a bicycle in row 1? Then when we move to larger n the training wheels are no longer needed?

 

>>766

Thanks, Teach. Glad to have you dropping knowledge here. Love this community of MathFags. You all rock. More rare hitlers? You now have your own rare Pepe! :)

 

One day (maybe) we all meet up at Tony Stark (VQC's) lair and hang out IRL for a coffee or beer. Even my wife is like "You're so happy working on math(s). You must really like these MathFags." I'm like "yeah, I never knew how much I love math and MathFags."

VeritasAequitas !!Nf9AmQNR7I ID: 1d0be2 Dec. 20, 2017, 10:18 p.m. No.776   🗄️.is 🔗kun   >>777

>>772

>>771

Alright you two. Get a room, LOL! You know I can understand any idea you propose, but can't code it for shit. What you cooking up? Can you fill in an AlgebraAnon PLS? What's the pattern/equation faggots? Um, we have no pattern yet, right? However, it's soon to be discovered!

VeritasAequitas !!Nf9AmQNR7I ID: 1d0be2 Dec. 20, 2017, 10:50 p.m. No.792   🗄️.is 🔗kun   >>794

>>787

Wait, d is the perfect square with remainder e. a is the small square. X is a derivative of d-x. x will always be smaller than a. Confirm?

VeritasAequitas !!Nf9AmQNR7I ID: 1d0be2 Dec. 20, 2017, 11:17 p.m. No.810   🗄️.is 🔗kun

>>796

No worries, we have a great baker! Teach, just keep whiteboarding everything. Work, brother the next bake is in good hands.

 

>>782

>>793

PMA rocking it.

 

>>791

Baker, nice pics!

 

>>797

(0,1)(1,1)(2,1)(3,1) etc.

(0,2)

(0,3)

(0,4)

etc.

 

Patterns.

 

KEK RULES!

E

K

 

R

U

L

E

S

!

VeritasAequitas !!Nf9AmQNR7I ID: 1d0be2 Dec. 20, 2017, 11:44 p.m. No.822   🗄️.is 🔗kun   >>862

>>817

Well shit, thanks for the memes.

In return, here you go.

When go got to post, go to the name field.

Enter yourname##password. Simple as that.