Choose a prime number that is a factor of any value of a in a cell in the first row (e,1).
E.g. 5
E.g. (1,1)
5 appears as a factor of a in the second element (1,1,2,3,5,13) 5x13=65
5 will be a factor of the 2nd,7th,12th,17th value of a in (1,1)
5+1 is 6. 5 will be a factor of a in the (6-2) element at (1,1)
The fourth element is 25.
Five will be a factor of the fourth, ninth, fourteenth, nineteenth element of (1,1).
This is true of any factor p in any cell in row (e,1).
If first appearance of factor p is element t, second appears will be at (p+1-t)
p will be a factor of a in elements:
t+p, t+2p, t+3p,..
and
p+1-t, 2p+1-t, 3p+1-t,..
Since xx+e = 2na, every cell in row (e,1) contains a catalog of all values of na for a remainder e within the value a for those elements.