Is that it!!! You know e so all you have to do is search column (e,1).
By by RSA!
Its been great!
Big step but more to go!>>495
Sorry for excitement!
In the zero columns since e is zero 2an =x^2
Problem is to solve for n where a and b are prime. in record (0,2,c^2,x,a^2,b^2) you can solve for n in terms of a and b.
x=a^2(b^2-1)
2an=x^2
n=a^2(b^2-1)^2
S>>854
sorry
n=a^2(b^2-1)/2
Sorry again
record is (0,n(c^2),c^2,x,a^2,b^2) so you can solve n for squared record in terms of square of original primes.
n(c^2)= a^2(b^2-1)/2
To be clearer
For record (0,n(c^2),c,x(c^2),a^2,b^2)
for primes a,b
x(c^2)^2=2a^2n(c^2)
x(c^2)=a^2(b^2-1)
n(c^2) =a^2(b^2-1)/2
using x(c^2) and n(c^2) to distinguish from x and n for record (e,n,c,x,a,b)
Fucked up!
n(c^2)=a^2(b^2-1)^2/2
for c^2=a^2*b^2