VeritasAequitas !!Nf9AmQNR7I ID: feb7e0 Dec. 18, 2017, 11:55 a.m. No.339   🗄️.is 🔗kun   >>342

>>337

Yeah, hopefully Teach can confirm one way or another. It only works in (e,1) at the moment, so we still have to figure out (e,n) pattern for t like you said. Thanks for all your excellent work!

VeritasAequitas !!Nf9AmQNR7I ID: feb7e0 Dec. 19, 2017, 9:21 a.m. No.500   🗄️.is 🔗kun

>>495

Cool, thanks VQC! "Every cell in row 1 contains a catalog of all values for na remainder e." So t will work fine as our index variable If our catalog of values remains in (e,1). So starting with c, we get d and e. Then e sends us to the correct column in row 1. Then we use our "catalog of factors" which is tied to the "s = t(a)" crumbs that Senpai dropped a few nights back to know how far up to ride the t elevator. I'll review the crumbs about factors and var s and get back to work.

VeritasAequitas !!Nf9AmQNR7I ID: feb7e0 Dec. 19, 2017, 11:46 a.m. No.505   🗄️.is 🔗kun

Hello everyone! For looking over everything for factor patterns to build the catalog of factors, we have this super clear work from PMA. It's cells (1,1) and (2,1) for t values 1-100.

>>>/CBTS/100653

>>>/CBTS/100657

VeritasAequitas !!Nf9AmQNR7I ID: feb7e0 Dec. 19, 2017, 2:29 p.m. No.543   🗄️.is 🔗kun   >>544 >>545

>>536

>>537

>>538

If e is odd, at t=1 a = (e+1) /2. Then use d-a= x to get your x var, and solve for b var.

If e is even, at t=1 a = e/2. They use d-a to get x, solve for b.

 

So at t=1 for row 1 we can start with nothing but c and populate the element with d, e, a, x, b. Can we verify n=1 too?

 

Now let's find out how p lets us scale up with correct a var values as t increases. Thoughts, anons?

VeritasAequitas !!Nf9AmQNR7I ID: feb7e0 Dec. 19, 2017, 2:34 p.m. No.544   🗄️.is 🔗kun

>>543

And knowing x allows us to create index var t, as well.

 

Looks like Teach and baker are working on scaling up!

VeritasAequitas !!Nf9AmQNR7I ID: feb7e0 Dec. 19, 2017, 3:55 p.m. No.563   🗄️.is 🔗kun   >>565

>>545

Teach, I agree. I think following the a var is the key. VQC keeps hinting at it. when we can find a way to solve for a in all cells (e,n) then we can create all the remaining vars in that element, and possible fill out the cell too. c, d, e, a, x, t (if needed?) b, and n. In that order of discovery I think.

 

I'm going to keep my focus in row 1 for now, and try to unlock how everything moves for a, x, t, and b. I know it's been discussed, but Notice Again that in all row 1, var b for t=1 becomes var a in t=2, and then you can solve for b. Then b drops to next var a, ad infinitum. Works for all row 1.

VeritasAequitas !!Nf9AmQNR7I ID: feb7e0 Dec. 19, 2017, 4:06 p.m. No.568   🗄️.is 🔗kun

>>565

Agreed! I still haven't figured out how this works in other rows. Also, why some cells aren't populated. Any Anons figured out why this occurs? I've seen some hints and ideas, but not a clear explanation yet.

VeritasAequitas !!Nf9AmQNR7I ID: feb7e0 Dec. 19, 2017, 4:09 p.m. No.569   🗄️.is 🔗kun   >>585

>>567

Nice! Baker gotz all the ponies in his stable. ;) I'll leave it at that, or Topol will start blowing up the thread with Brony videos, lol!

VeritasAequitas !!Nf9AmQNR7I ID: feb7e0 Dec. 19, 2017, 4:18 p.m. No.576   🗄️.is 🔗kun   >>578

>>571

Nice work, MA! Thanks for always posting cool shit like this. (You) got a compliment from our Senpai. Even if it's a larp (my gut says it's legit) at least we've had lots of fun making cool shit, enjoying math, and talking about crazy ideas.