VA !!Nf9AmQNR7I ID: 341dcd Jan. 6, 2019, 5:39 p.m. No.8520   ๐Ÿ—„๏ธ.is ๐Ÿ”—kun

>>8499

Hmmm. (1,1) is one of the most important cells. So I started there looking for patterns. Interesting find for a *b values moving diagonally in the Grid from (1,1). Found the following combos:

(4,4) a * an

(9,9) BigN * c

(25,25) an * c

(49,49) a * c

VA !!Nf9AmQNR7I ID: 341dcd Feb. 14, 2019, 7:39 p.m. No.8571   ๐Ÿ—„๏ธ.is ๐Ÿ”—kun   >>8572

I just noticed a cool pattern.

Starting at the (na transform) element,

a[t] (e) - a[t] (-f) = an increasing pattern.

128-127=1

100-97=3

76-71=5

56-49=7 which is (n-1)

So the difference between a[t] (e,1) compared to a[t] (-f,1) moves upward in an ascending pattern until the first element in a given e column.

for odd e, (e+1)/2 = a[1]

So this info greatly limits our search area.

Thinking out loud over here.

We limit the search using the (na transform) element and the a[1] element.

VA !!Nf9AmQNR7I ID: 341dcd Feb. 14, 2019, 8:42 p.m. No.8572   ๐Ÿ—„๏ธ.is ๐Ÿ”—kun

>>8571

To be clear, Iโ€™m not suggesting iterating by x.

Iโ€™m suggesting using every available piece of info to limit the search area.

BigN is also a limiting piece of info

Along with 2(sqrt((f-1)/8)-1

Set boundaries, then factor

VA !!Nf9AmQNR7I ID: 341dcd Feb. 14, 2019, 9:06 p.m. No.8573   ๐Ÿ—„๏ธ.is ๐Ÿ”—kun

More patterns.

This one has (-f,1) a[t]=c and its equivalent element in (e,1) is distance of (a) apart, 287 - 270= 7 = correct a value

Also, the a[t] = (bn) value = 328

in (e,1) 328 - 287 = 41 = b

so c, a, and b are available/calculable in a triangle pattern right next to each other in adjacent elements.

Here's a diagram.

VA !!Nf9AmQNR7I ID: 341dcd Feb. 14, 2019, 9:34 p.m. No.8574   ๐Ÿ—„๏ธ.is ๐Ÿ”—kun   >>8575

Once you c it you canโ€™t un-c it?? Why does a[t]=c appear in many of our cases?

 

for c287

2(sqrt(d))-1 = 7 = (n-1)

Must be a fluke, but still analyzing for patterns over here.

 

Lol, for c6107 2(sqrt(d))-1= 15 and correct (n-1)=35

Shared factor of 5. Interesting.

and 2(sqrt((f-1)/8)-1 = 7 which is another factor for 35

 

Hello PMA, Jan, and 5DAnon can I please request your assistance?

Could it be a characteristic of ONLY semiprime c values that we always have one a[t]=c element?

Makes sense that c always appears at a[t] since the prime factors have to show up again.

VA !!Nf9AmQNR7I ID: 341dcd Feb. 14, 2019, 9:37 p.m. No.8575   ๐Ÿ—„๏ธ.is ๐Ÿ”—kun

>>8574

And if that element exists for a given semiprime c, we can solve the problem with the adjacent elements. (maybe!)

 

You guys know how I work, calculator in hand with a pencil at the ready. If the idea sucks, that's fine. Working from small examples over here.