Anonymous ID: 609e7d Nov. 28, 2018, 12:24 p.m. No.8397   🗄️.is 🔗kun   >>8398 >>8399

>>8396

AA and Jan, since we're not that many people left still discussing things I'm asking you two a bit more directly. Have we identified any of these two equations VQC has talked about? I know we have a lot of equations and he has talked in the past about two branches of math meeting, solving two equations in tandem(?)/parallel only to have them meet and combine, which will become a new thing.

 

My initial though is that he might be referring to the multiplication of -f and e. Since we know they will not be of the same parity, we then also know that they will have a different set of equations for the a-values. If f is even then a's are 2 squares - f/2, and a-values in e will be 4 triangles + (e + 1)/2. If f is odd then a's are 4 triangles - (f - 1)/2 and e will be 2 squares + e/2. These are two "different" equations, meeting (in the exclusive middle?).

 

But how would those spiral?

 

Also to note, I'm asking because I'm not sure, but I personally doubt that we're talking about the equations for 'a' alone here.

Anonymous ID: 609e7d Nov. 28, 2018, 12:37 p.m. No.8398   🗄️.is 🔗kun

>>8397

Based on previous posts and work we've done, I would assume that one of the equations is nn + 2d(n - 1) + f - 1. Or PMA's suggestion of nn + (2d - 1)(n - 1) + n - 1 + f - 1.

 

Assuming that is true, and we're going to combine the triangular solution with the recursive function, then we will end up with a tree and parts of that equation. We'll know 2d, f and -2. Somehow, this is going to be connected to the tree and the grid.