Don't sweat it.
I've been spending some more time looking into the smooth numbers. I've noticed that given (e, n) the smooth numbers for those records (bigN - n) exists in (e - 2*n, 1). If e is odd, then the smooth numbers will exist as d's. If e is even then smooth number will appear as a. If you jump to (e + 2n, n) the smooth values of those records will match the a's or d's in (e, 1) at t for bigN. Essentially, given a record a, b we get bigN. If e is odd then the d at a[t] = aBigN (e, 1) will be a "smooth" number for the jump (or a + 1, b + 1) in (e + 2n, n).
The smooth numbers of (0, 1) exist in (-2, 1) at t = 1, 4, 9, 16…
The smooth numbers of (1, 1) exist in (-1, 1) at t = 1, 4, 9, 16…
It also appears that the t's for the smooth numbers in (e, 1) exist in (e - 1, 2). Although that is just a preliminary result. I haven't had much time to look into that result.
The patterns aren't always [1, 4, 9, ..] but offsets.
Take (7, 1). The first 10 smooth numbers are:
[2, 5, 10, 17, 26, 37, 50, 65, 82]
Here the relationship with squares is 2 + 2, 5 + 4, 10+6, 17 + 8.
(8, 1) has first 10 smooth numbers: [4, 8, 14, 22, 32, 44, 58, 74, 92] which has the pattern 4 + 0, 8 + 1, 14 + 2, 22 + 3, 32 + 4 …
Take cell (3, 6). Moving to the left will put us in (3 + 2*6, 6) =(15, 6).
The first 10 rows in (3, 6) is:
and their smooth numbers are:
{3:6:4:3:1:19}
{3:6:16:9:7:37}
{3:6:34:15:19:61}
{3:6:58:21:37:91}
{3:6:88:27:61:127}
{3:6:124:33:91:169}
{3:6:166:39:127:217}
{3:6:214:45:169:271}
{3:6:268:51:217:331}
{3:6:328:57:271:397}
[0, 108, 540, 1620, 3780, 7560, 13608, 22680, 35640]
While the first 10 rows in (15, 6) are:
{15:6:17:9:8:38}
{15:6:35:15:20:62}
{15:6:59:21:38:92}
{15:6:89:27:62:128}
{15:6:125:33:92:170}
{15:6:167:39:128:218}
{15:6:215:45:170:272}
{15:6:269:51:218:332}
{15:6:329:57:272:398}
{15:6:395:63:332:470}
and their smooth numbers are:
[129, 579, 1683, 3873, 7689, 13779, 22899, 35913, 53793]
Note that (15, 6) has "shifted" one record down, meaning the first cell in (3, 6) (a=1, b=19) is gone.
Each of the smooth numbers in (15, 6) are the d's at (3, 1) where a[t] = BigN.
The big n for a=7, b=37 is 114 and the d at that location = 129 and exists at t = 8.
This means that the t's in (3, 1) where d = smooth number for (15, 6) are: [8, 17, 29, 44, 62, 83, 107, 134, 164]
Minor typo, pasted the records along with the smooth numbers, but you'll see the difference.
The smooth numbers for (3, 6) (0, 108, …) exists in (3 - 2*6, 1) =(-9, 1) at t's: [2, 8, 17, 29, 44, 62, 83, 107, 134]
Which we can see occur at the same location in (3, 1) as the smooth numbers do for (15, 6).
Hey man, that's understandable. You need to take care of yourself. You've done a massive job and I'm very impressed (and a bit guilty for not participating as much in the pattern thread). I hope you'll straighten things out.