n values for the first 28 triangle numbers (from ColumnKeys function)

T(1) = n/a

T(2) = [1]

T(3) = n/a

T(4) = n/a

T(5) = [1, 5]

T(6) = [1, 7]

T(7) = [3]

T(8) = [4]

T(9) = [1, 3, 17]

T(10) = [1, 21]

T(11) = n/a

T(12) = n/a

T(13) = [1, 37]

T(14) = [1, 3, 9, 43]

T(15) = [1, 3, 7, 21]

T(16) = [8, 24]

T(17) = [1, 15, 65]

T(18) = [1, 17, 73]

T(19) = n/a

T(20) = n/a

T(21) = [1, 5, 25, 101]

T(22) = [2, 112]

T(23) = [10, 54]

T(24) = [3, 11, 59]

T(25) = [1, 17, 145]

T(26) = [2, 6, 42, 158]

T(27) = n/a

T(28) = n/a

>>7007

It returns pairs of n and n-1.

For example, if we input -24, 1 it will return

[[4, 5], [60, 61]]

since -f and e combined make the columns unique to c. Can this function be reconstructed from a description of how it behaves?

This is a diagonal, since it describes pairs of n that are one (row) apart. How do column -f and e when used together at once materialize the solution, since the diagonal and the patterns they make when used in tandem are unique to c?

It will all make sense in hindsight.