α = T(c-2) + ((c-e)/2)

γ = T(c-1) + ((c-f-1)/2)

δ = T(c-1) + (c-e-1/2)

Observed with c34117 (data in the main thread):

(-f, 1, (d+N))[b] - α = x+1

γ - α - c = x

γ - δ = x+2

Observed with c6107 (data in the main thread):

(e, 1, (d+N)[b] - (e,1,(d+N)[a] - 2α = x-1

This occurs because

(e, 1, (d+N)[b] - (e,1,(d+N)[a] - 2α = 2e

and 2* e of 6107 = x-1

These variables are rearranged forms of formulae that generate the a[t] and b[t] values in the place where Chris hinted the lookup would be in. (t) and (i) -set t = -i and x=-c