Anonymous ID: 8d5142 Dec. 28, 2017, 9:51 p.m. No.1535   🗄️.is 🔗kun   >>1536 >>1543 >>1546 >>1554 >>1603

Hi anons and namefags. Your old pal TLA here; was doing family stuff too over xmas. I'll try to get back into this but I am on the road so will be limited. Also battery running out here.

 

These threads would be easier to follow, for me, if they were written in mathese: propositions, lemmas, laws, identities etc. But that's ok, I will just have to dig in and try to interpret. Then translate if I can. For now just two simple questions if any anons wouldn't mind answering.

 

First, given c, where c=ab and a, b are unknown, are anons trying to 'travel' to the 'record' ending in { …. a:b} ? Because it doesn't seem like that's what VQC was hinting at. Rather, that the factors would be 'exposed' in some way.

 

Second, as far as this hint:

>>1099

Have anons realized that there should be four 'records' with product c^2? these would be

1*aabb

a*abb

aa*bb

b*baa

 

(assuming a <b ). Gonna have a look at some of these tonight.

 

Unlike some of you, my redpilling the family attempts did not go well and I am a bit sad about that. I figure, at least, I will have softened them up a bit. My sister even thinks Antifa is cool and doesn't wanna hear otherwise :( cheer me up anons, and keep up the good work.

Anonymous ID: 8d5142 Dec. 28, 2017, 9:55 p.m. No.1540   🗄️.is 🔗kun

>>1536

I will do this, going over all VQC's posts, and trying to keep it purely pertinent. I will do it over the next few days and if VQC just lets it all out first, all the better.

Anonymous ID: 8d5142 Dec. 28, 2017, 10:30 p.m. No.1548   🗄️.is 🔗kun

>>1546

haha you call me a cunt all you want, you wonderful anonymous cunt you. i am actually very fascinated by what you call memetics, though I've never used that word. indeed there is an art to informing the ignorant, and this great meme war is sure sharpening that up. guess I was hard on myself for not being better at it.

 

one more math thing, maybe not relevant, but I worked on this on the bus a few days ago so I'll spill it. VQC mentioned sums of squares being closed under multiplication. i.e. (xx + yy)(ww + zz) = ss+tt, another sum of squares. this can be proved with Gaussian integers (complex numbers a +bi where i = sqrt(-1) ), which gives a formula for two possibly different ways to write the resulting product as sum of squares:

 

(xx + yy)(ww+zz)

= xxww + yyww + xxzz + yyzz

= xxww + 2wxyz + yyzz + xxzz - 2wxyz + yyww

=(wx+yz)^2 + (xz-yw)^2,

 

or else (wx -yz)^2 + (xz+yw)^2 by switching the + and - .

 

VQC's mention might only be incidental though, part of the grid, and not going to be part of the factoring process.