dChan
Anonymous ID: 514adc March 3, 2019, 5:28 a.m. No.8661   🗄️.is 🔗kun   >>8662 >>8663

>>8650

While VQC is finishing his family lunch, I'm going to just do some prep to see if I'm on board.

 

LookupT(145) =67, 1, 24

 

So at (1, 1, 67) (e,n,t) we have 145 * 61, and this record also exists in e=1, f=-24.

 

We know the record a=5, b=29 exists in (1, 5) and in (-24, 4).

 

>>8652

The square of 145 exists in (0, 1, 145), (0, 1, 145*2) ..

 

The question then is

>X and Y are the positions of n between 1 and the square of c

 

Are we referring to the two n-values as in n=5 and n=4, or the bigN and the mirror bigN?

 

We know c^2 exists in both (0, 1) and (1, 1). In the first column it's the a-value and exists at x=2c, while in the second it's a d-value and exists at x=(2c-1).

 

>>8650

Also:

> LookupT is used by LookupN.

A reference to the recursiveness of the algorithm? If so, we're then dealing with first starting from c, finding some record based on this and then continue?

Anonymous ID: 514adc March 3, 2019, 5:43 a.m. No.8662   🗄️.is 🔗kun   >>8663 >>8691

>>8661

>>8652

>X and Y will not exist for primes (that depends on the value of f and d).

 

Which leads me to believe it's a reference to the n-values and not the bigN, since a prime number only has bigN-values. This X and Y won't exist from primes numbers.

Anonymous ID: 514adc March 3, 2019, 6:50 a.m. No.8664   🗄️.is 🔗kun   >>8665 >>8666 >>8831

>>8663

I'm seeing this as two possible things, either it is a reference to the pattern:

a[t] = bn

d[t - 1] - d = b(n-1)

 

or, it's more literal as in there are two values in (e, 1) where (d[t] + x)/2 = d. As in, d is between these two numbers.

 

For the first part I haven't had luck in the past trying to figure out how to take advantage of it, since (-f, -1) the a-values are all equal to the d[t] - d from (e, 1). The d[t - 1] is a point, however, to how the patterns move. Since -f is looking at c from another perspective (d + 1) you can look at c from multiple such perspectives (d + 1 … 10000) and you'll see how the t-patterns moves as a square throughout all the f-s (or rather a grid of squares).

 

For the second idea we have to involve the negative x-values, something you've been pushing on us a lot. So for our example of c=145, d = 12. If we're after the midpoint, that is where (d[t] + d[k])/2 = d we have d[2] = 8 and d[5] = 32.

 

(-8 + 32)/2 = 12 and (8 + (-32))/2 = 12.

 

In this case d[2] = 8, a[2] = 5 and d[5] = 32, a[5] = 25.