Anonymous ID: 5dbbb1 March 9, 2019, 7:44 a.m. No.8787   🗄️.is 🔗kun   >>8788

>>8773

>Why are we using alternating primes, though?

Was Oddly confused. See >>8748

Definition:Odd Prime (https://proofwiki.org/wiki/Definition:Odd_Prime)

  • Apart from 2 itself, all primes are odd.

  • So, referring to an odd prime is a convenient way of specifying that a number is a prime number, but not equal to 2.

 

>>8779

>If q is the product of the set of small primes and c'=abq = qc, and d'd'+e' = c', and a must appear twice in the first a+1 [e',1,t] elements of [e',1], how do we know what factors will also make up the two values of t where a is a factor of [e',1,t]?

Nice notation! Will work on this.

 

>>8780

>I can understand using primes that are only the sum of two squares as an accelerant for certain c, but remove 23 and other primes that end in 11 in binary, the sum of two squares that are odd end in 01

Ah, i c. Also can clearly see '2' as the oddball ending in zero! And won't be able to eliminate in decimal form, as those ending in '3', '7', '9' are all a mixed bag of '01' and '11' in binary form.

2 → 0000000000010

3 → 0000000000011

5 → 0000000000101

7 → 0000000000111

11 → 0000000001011

13 → 0000000001101

17 → 0000000010001

19 → 0000000010011

23 → 0000000010111

29 → 0000000011101

31 → 0000000011111

37 → 0000000100101

3881 → 0111100101001

3889 → 0111100110001

3907 → 0111101000011

3911 → 0111101000111

3917 → 0111101001101

3919 → 0111101001111

 

Will generate new list (5, 13, 17, 29, 37, 41, 53, 61, 73, etc.)

 

Oh, i c more correlations! (https://oeis.org/A002144)

A002144 Pythagorean primes: primes of form 4n + 1.

5, 13, 17, 29, 37, 41, 53, 61, 73, 89, 97, 101, 109, 113, 137, 149, 157, 173, 181, 193, 197, 229, 233, 241, 257, 269, 277, 281, 293, 313, 317, 337, 349, 353, 373, 389, 397, 401, 409, 421, 433, 449, 457, 461, 509, 521, 541, 557, 569, 577, 593, 601, 613, 617

COMMENTS

  • Rational primes that decompose in the field Q(sqrt(-1)). - N. J. A. Sloane, Dec 25 2017

  • Odd primes such that binomial(p-1, (p-1)/2) == 1 (mod p). - Benoit Cloitre, Feb 07 2004

  • Primes that are the hypotenuse of a right triangle with integer sides. The Pythagorean triple is {A002365(n), A002366(n), a(n)}.

  • Not only are the squares of these primes the sum of two nonzero squares, but the primes themselves are also. 2 is the only prime equal to the sum of two nonzero squares and whose square is not. 2 is therefore not a Pythagorean prime. - Jean-Christophe Hervé, Nov 10 2013

  • The statement that these primes are the sum of two nonzero squares follows from Fermat's theorem on the sum of two squares. - Jerzy R Borysowicz, Jan 02 2019

  • The decompositions of the prime and its square into two nonzero squares are unique. - Jean-Christophe Hervé, Nov 11 2013. See the Dickson reference, Vol. II, (B) on p. 227. - Wolfdieter Lang, Jan 13 2015

  • p^e for p prime of the form 4*k+1 and e>=1 is the sum of 2 nonzero squares. - Jon Perry, Nov 23 2014

  • Primes p such that the area of the isosceles triangle of sides (p, p, q) for some integer q is an integer. - Michel Lagneau, Dec 31 2014

 

and our primes ending in binary '11'?

A002145 Primes of the form 4n+3. (https://oeis.org/A002145)

3, 7, 11, 19, 23, 31, 43, 47, 59, 67, 71, 79, 83, 103, 107, 127, 131, 139, 151, 163, 167, 179, 191, 199, 211, 223, 227, 239, 251, 263, 271, 283, 307, 311, 331, 347, 359, 367, 379, 383, 419, 431, 439, 443, 463, 467, 479, 487, 491, 499, 503, 523, 547, 563, 571

  • Or, odd primes p such that -1 is not a square mod p, i.e., the Legendre symbol (-1/p) = -1. [LeVeque I, p. 66]. - N. J. A. Sloane, Jun 28 2008

  • Primes which are not the sum of two squares, see the comment in A022544. - Artur Jasinski, Nov 15 2006

  • Natural primes which are also Gaussian primes. (It is a common error to refer to this sequence as "the Gaussian primes".)

  • Inert rational primes in the field Q(sqrt(-1)). - N. J. A. Sloane, Dec 25 2017

 

Validating:

3 → 0000000000011

7 → 0000000000111

11 → 0000000001011

19 → 0000000010011

23 → 0000000010111

31 → 0000000011111

43 → 0000000101011

499 → 0000111110011

503 → 0000111110111

523 → 0001000001011

547 → 0001000100011

563 → 0001000110011

571 → 0001000111011

Anonymous ID: 5dbbb1 March 9, 2019, 9:02 a.m. No.8789   🗄️.is 🔗kun   >>8790

>>8788

Very interesting, would Gauss the proof for that is Legendre! j/k

Looking at a 1956 paper by N. C. Ankeny titled "Sums of Three Squares" seems related as well.

Journal: Proc. Amer. Math. Soc. 8 (1957), 316-319

http://www.ams.org/journals/proc/1957-008-02/S0002-9939-1957-0085275-8/S0002-9939-1957-0085275-8.pdf

Hmm, wondering if this pattern is linked to the trivial solution of Fermat's Theorem mentioned early on as well…

Anonymous ID: 5dbbb1 March 9, 2019, 12:33 p.m. No.8792   🗄️.is 🔗kun   >>8793 >>8794 >>8934

>>8790

Indeed, ty.

In the End, perhaps math and programming go together. This journey sparked a coding path (crawling, looking forward to first baby steps) in parallel with the maths. Grateful.

Funny, was distracted yesterday by the Prime conspiracy on Rosetta Code.

https://rosettacode.org/wiki/Prime_conspiracy

So pulled in the code and ran it (cap in pic).

Today, wanted to regenerate for the last two digits using binary format, but trying to stay focused given limited Time.

 

Ran into an interesting book, same topic of this Primal Conspiracy…

https://mitpress.mit.edu/books/prime-number-conspiracy

 

and for some comfy music a little Chris Crummey and the Searchers. May he R.I.P.

 

>>8791

Gotta DASH! (and stop flirting with Julia!)

Anonymous ID: 5dbbb1 March 9, 2019, 5:46 p.m. No.8799   🗄️.is 🔗kun

>>8795

>>8796

Farted around with it a bit, pulled some stuff from the net, and can generate Julia Set (see cap).

Haven't done the full animation piece, it's back to the Grid…

Anonymous ID: 5dbbb1 March 9, 2019, 6:07 p.m. No.8801   🗄️.is 🔗kun

>>8800

>Next we have this to work on: >>8779

>The element you've verified in the new (e,n) is the BigN element.

>Next we need to explore (e,1) to find the element with the same c'=abq or (an) or (prime b) or any other piece of info that can solve the problem.

ty Anon, and nice dubs. Agree this is next step.

Do your thang, keeping commitments is important!!! (Promises Kept!).

Go and project selfless love to those you're with. You'll come back ready. Fresh.

Anonymous ID: 5dbbb1 March 11, 2019, 7:21 p.m. No.8816   🗄️.is 🔗kun   >>8817 >>8818 >>8820

>>8814

Hi AA, did you catch the part about Pythagorean primes? (the two ending bits being one method to identify).

In your qc = 456015, you're using 3, 5, and 7 as your helpers.

3 x 5 x 7 x 43 x 101 = 456015.

 

Not sure how important the Pythagorean helpers are vs. regular primes?

Those would be: q=5x13x17=1105

qc = 1105x4343 = 4799015

 

qc = 4799015

d_raw = 2190.6654

d = 2190

d^2 = 4796100

(d+1)^2 = 4800481

e = 2915

a = 1

b = 4799015

f = -1466

x = 2189

 

>>8813

>from t=1 to t=a+1 where a'[t]%a==0:

That looks like a nice approach!

Was playing with that earlier in [0,0] looking for n*a==c'. Wasn't quite the right direction (c' gives max possible n, looking for X and Y), because given the number is composed of primes, nothing there, need to go to -f and e and e' to find them.

 

For the pythagorean primes, generated a list of primes and then filtered. using the form 4n+1 (ref here: https://oeis.org/A002144).

  • Other approach was to generate a list of the integers in that form, and then filter the list to get the primes set. But, we don't really need too many so can just grab from that web list for now.

  • couple pretty related pics attached, just from web.

  • limited time to work on this again and behind the curve.

 

>>8815

>I think the main point of this c'=abq=qc is to get (prime a) or (prime b) to "fall out"

  • seems to be the case. Collect a relatively large number of candidate factors from the places indicated using lookup matches, then "Rule" them out, as "There can only be ONE".