Anonymous ID: 741f82 March 9, 2019, 12:25 a.m. No.8779   🗄️.is 🔗kun   >>8787 >>8800 >>8801 >>8813

If q is the product of the set of small primes and c'=abq = qc, and d'd'+e' = c', and a must appear twice in the first a+1 [e',1,t] elements of [e',1], how do we know what factors will also make up the two values of t where a is a factor of [e',1,t]?

 

That is the question we're answering.

That is also the two values we are forcing with the grid.

 

This is the basis of the non-trivial Lookup.

Anonymous ID: 741f82 March 9, 2019, 12:35 a.m. No.8780   🗄️.is 🔗kun   >>8787 >>8836

>>8771

I can understand using primes that are only the sum of two squares as an accelerant for certain c, but remove 23 and other primes that end in 11 in binary, the sum of two squares that are odd end in 01.