Dead as usual with no semblance of a kept promise.

Still trust Chris?

You all must be so tired of being manipulated.

Do you want an end to this?

>>9383

Okay

>>9385

Column 0 solution

Are we already past knowing where e and f have a bearing in column zero?

>>9391

I've given some of the hints that this board enjoyed when they had nothing else and I want to continue in a more open manner

One of the hints that was given when the tree structure was proposed was that it required factorising d and e

A factor of d is a factor of dd, much like if a or b had factors, they would be factors of c

>>9390

A mathematical relationship

>>9393

It is a spiritual position

If we were to look at an element that is d * d, a + b for that element would be (d + d), or 2d, and it would exist in (0, 0, d).

If they existed we would find subsequent factorisations in (0, n) where d[t] = d

If values that were not differences of squares were encountered, we would divide by two.

The goal of looking at column zero is modus tollens. You may have heard that term before.

(0, e)

(0, f )

Where d^2 is between in c[t]

(Which is also where d is between in d[t])

Comparing these elements to where d is between in d[t] in row one gives the solution

The elements for the factorisation(s) of dd in column zero are linked to the elements d is between in column zero and row one and link to the factorisation of c via i[t]