Anonymous ID: 9f00d8 July 15, 2019, 8:35 p.m. No.9605   🗄️.is 🔗kun   >>9606 >>9611

>>9601

You should expect to find c-relevant values in gaps between element values, since (e, 1) isn’t tailored directly to c, but is a cell representing the whole column.

 

If you’re wondering what could be useful at a pair of elements where x adds up to a specific thing, maybe it would help you to consider it a pair of x and n. Either would be valid. The grid’s all about squares and the patterns have squares in their squares.

Anonymous ID: 9f00d8 July 15, 2019, 9:46 p.m. No.9625   🗄️.is 🔗kun

>>9622

At the point where two x values from the opposite columns add up, the difference in f will be that sum + 2.

 

Example: for aforementioned elements, x+x = 25, f - f = 27

Anonymous ID: 9f00d8 July 15, 2019, 10:07 p.m. No.9629   🗄️.is 🔗kun

>>9628

So you do have an idea of what the solution looks like. Can I tell you that it isn’t complicated and can be rewritten into different ways? A solution might look like that long tree, but remember, it was also said that there were grid shortcuts. Don’t forget, the grid still confuses even the person who brought it to us.

Anonymous ID: 9f00d8 July 15, 2019, 10:09 p.m. No.9630   🗄️.is 🔗kun   >>9632 >>9634

“Fractal nature of the solution.”

 

What is a fractal, but doing the same thing over and over? Kind of like calculating c over and over? How are you doing that when you input grid coordinates without realizing it?

Anonymous ID: 9f00d8 July 15, 2019, 10:33 p.m. No.9635   🗄️.is 🔗kun   >>9636

The amplitudes of qubits can contain values that you can’t put on a number line.

The same is true for elements.

How would you use those? )(It’s not a coincedence q gets the same variable name as Quantum, so what’s special about that process?)