>https://archive.fo/RgVko (RSA#1)
VQC:
Anonymous 12/05/17 (Tue) 09:34:37 ID: ecb64b No.36154
I'll work through RSA100. If you're using C# the BigInteger namespace is handy.
c = 1522605027922533360535618378132637429718068114961380688657908494580122963258952897654000350692006139
d = 39020571855401265512289573339484371018905006900194
e = 61218444075812733697456051513875809617598014768503
n = 14387588531011964456730684619177102985211280936
x = 1045343918457591589480700584038743164339470261995
a = 37975227936943673922808872755445627854565536638199
b = 40094690950920881030683735292761468389214899724061
In the element at (Rsa100e,1) you find that the element where x = Rsa100x, you will find a = Rsa100n x Rsa100a
If you find a that is Rsa100n elements further down, then that a will equal Rsa100n x Rsa100b
Then at grid cell (Rsa100e, Rsa100n) which is obviously in the same column, you'll find the product c.
In summary, the factors in any cell in the first row govern ALL the behaviour in the column below in a pattern or, if you perfer, in MANY patterns.
A member of Pink Floyd said in an interview during a documentary on MUSIC PRODUCTION that the GAPS are absolutely as important as where there are NO gaps.
Let the VQC take the strain. The more you c it's beauty, the more it will give you (back).
You all amaze me.
Can't find the crumb, but VQC mentioned we can take a prime of our CHOOSING. The crumb you pulled is an example of this, using 5.