VA !!Nf9AmQNR7I ID: fc4336 Jan. 28, 2018, 10:14 p.m. No.3552   🗄️.is 🔗kun

>>3551

Thanks for understanding my idea, Baker. It's so nice to be with your minds who can do the things I like to do. Most people around me can't even begin to understand how excellent this forum is.

Just doing Math(s) is/are? improving my life.

 

The relationship between d, x, and a is amazing. I'm wondering if there's a pattern between [delta]t for (1,c) and t for (Prime Solution). Can we run those numbers, programAnons? Let's take known c's from the basic grid so everyone can follow. Let's do the (1,c) and (Prime) for each c value. If willing, PMA, would you please pick some c values starting at c=145 and greater? Just a few examples needed to examine this [delta]t idea between na=a for (1,e) and (e,n). Thoughts welcome.

VA !!Nf9AmQNR7I ID: fc4336 Jan. 28, 2018, 11:03 p.m. No.3558   🗄️.is 🔗kun

>>3555

Checked!!

 

Agreed. But if we can go from (1,c) to (prime) using a formula based on t in (e,1), then that gives us our x and t values, which are supposed to be the same in (e,n)?

 

>>3556

>>3557

Looks like this could be next steps for decision tree?

VA !!Nf9AmQNR7I ID: fc4336 Jan. 29, 2018, 9:45 a.m. No.3586   🗄️.is 🔗kun

>>3561

>>3562

>>3563 Factor Trees Crumb

>>3565 (N-1)a and na combined with Factor trees crumb? How to combine?

 

Thanks Baker for crunching the numbers for [delta]t. Seeing some very interesting patterns. You're right about the distance from T and t being too large in the RSA setting. Good progress on the (N-1)a and na ideas tho, and how they combine with the factor tree crumbs.

 

>>3576

Great find on this crumb!

 

>>3580

All right! Just saw this, VQC is back! Good to see you.

VA !!Nf9AmQNR7I ID: fc4336 Jan. 29, 2018, 6:48 p.m. No.3650   🗄️.is 🔗kun   >>3651

>>3649

I see where you're going Baker. Sum of (1,c) factors can be used to create all the remaining factors? However, checking your math wouldn't it be 12/2 = 2 and 6. Then 6 = 3 and 2? So the termination points would be 1, 2, 2, 3? Could be wrong here, just trying to make sure I understand what you're hinting at. Can you elaborate on your idea?

VA !!Nf9AmQNR7I ID: fc4336 Jan. 29, 2018, 8:38 p.m. No.3667   🗄️.is 🔗kun   >>3668 >>3669

>>3664

Thanks Anon!

 

>>3666

Interesting Malicious Digits, Checked!

 

So we sum all the "leaves" (termination points) in the whole circle/tree to find one prime factor? That should be easy to verify for you programAnons. Is that your idea Baker?

VA !!Nf9AmQNR7I ID: fc4336 Jan. 31, 2018, 9:29 p.m. No.3778   🗄️.is 🔗kun   >>3780

>>3776

>>3777

Checked 666 and 777? WTF Baker is on a roll!!! Here's a prophecy for the occasion:

"I see great and malicious confusion upon you, Baker. But the 777's of YHWH will deliver you and lead you to peaceful living space"

VA !!Nf9AmQNR7I ID: fc4336 Feb. 5, 2018, 7:09 p.m. No.4045   🗄️.is 🔗kun   >>4046

>>4043

And you can locate every position in the valley because c, d, and e. Like GPS. You have enough coordinate info to locate in more than 2D. E and f are the balance between two adjacent squares?

VA !!Nf9AmQNR7I ID: fc4336 Feb. 5, 2018, 10:58 p.m. No.4067   🗄️.is 🔗kun   >>4070

>>4066

Exactly! Thanks MM. (Mr. E. Melange?)

 

There are multiple answers for a given C? But only one is prime? What about the remainder of f? Factor f into d and e.